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Convert 2 km/h to m/s. How many ft/s is this?

Convert 2 km/h to m/s. How many ft/s is this?

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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### Converting Units and Expressing Values with Appropriate SI Prefixes **Conversion Problem:** **Convert 2 km/h to m/s. How many ft/s is this?** --- **Evaluation Problems:** Evaluate each of the following and express with SI units, using an appropriate prefix: (a) \((50 \, \text{mN})(6 \, \text{GN})\) (b) \((400 \, \text{mm})(0.6 \, \text{MN})^2\) (c) \(45 \, \text{MN}^3 / 900 \, \text{Gg}\) --- **Solution Steps:** 1. **Convert 2 km/h to m/s:** - \(2 \, \text{km/h} = \frac{2 \times 1000 \, \text{m}}{3600 \, \text{s}} = \frac{2000 \, \text{m}}{3600 \, \text{s}} \approx 0.556 \, \text{m/s}\) 2. **Convert m/s to ft/s:** - \(0.556 \, \text{m/s} \times 3.28084 \, \text{ft/m} \approx 1.82 \, \text{ft/s}\) 3. **Problem (a):** - \(50 \, \text{mN}\) (milliNewtons) = \(50 \times 10^{-3} \, \text{N} = 0.05 \, \text{N}\) - \(6 \, \text{GN}\) (GigaNewtons) = \(6 \times 10^9 \, \text{N} = 6,000,000,000 \, \text{N}\) - Result: \((0.05 \, \text{N}) \times (6,000,000,000 \, \text{N}) = 300,000,000 \, \text{N}^2 = 300 \, \text{GN}^2\) 4. **Problem (b):** - \(400 \, \text{mm}\) (millimeters) = \(400 \times 10^{-3} \, \text{m} = 0.4 \
Transcribed Image Text:### Converting Units and Expressing Values with Appropriate SI Prefixes **Conversion Problem:** **Convert 2 km/h to m/s. How many ft/s is this?** --- **Evaluation Problems:** Evaluate each of the following and express with SI units, using an appropriate prefix: (a) \((50 \, \text{mN})(6 \, \text{GN})\) (b) \((400 \, \text{mm})(0.6 \, \text{MN})^2\) (c) \(45 \, \text{MN}^3 / 900 \, \text{Gg}\) --- **Solution Steps:** 1. **Convert 2 km/h to m/s:** - \(2 \, \text{km/h} = \frac{2 \times 1000 \, \text{m}}{3600 \, \text{s}} = \frac{2000 \, \text{m}}{3600 \, \text{s}} \approx 0.556 \, \text{m/s}\) 2. **Convert m/s to ft/s:** - \(0.556 \, \text{m/s} \times 3.28084 \, \text{ft/m} \approx 1.82 \, \text{ft/s}\) 3. **Problem (a):** - \(50 \, \text{mN}\) (milliNewtons) = \(50 \times 10^{-3} \, \text{N} = 0.05 \, \text{N}\) - \(6 \, \text{GN}\) (GigaNewtons) = \(6 \times 10^9 \, \text{N} = 6,000,000,000 \, \text{N}\) - Result: \((0.05 \, \text{N}) \times (6,000,000,000 \, \text{N}) = 300,000,000 \, \text{N}^2 = 300 \, \text{GN}^2\) 4. **Problem (b):** - \(400 \, \text{mm}\) (millimeters) = \(400 \times 10^{-3} \, \text{m} = 0.4 \
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