CONVERSION OF UNITS Example 2: The density of gold is 19.3 g/cm³. What is the density in kg/m³? Solution: G: 19.3 W 19.33 Sm notes ✓ opines) K2) (1 cm) ³ = 19.3 kg 1X10 X10-61 I 1039 m3 Notes 19.3 ка kg = 19.3x 1x 10-3 m3 = 1.93 X 104 kg DE DO
CONVERSION OF UNITS Example 2: The density of gold is 19.3 g/cm³. What is the density in kg/m³? Solution: G: 19.3 W 19.33 Sm notes ✓ opines) K2) (1 cm) ³ = 19.3 kg 1X10 X10-61 I 1039 m3 Notes 19.3 ка kg = 19.3x 1x 10-3 m3 = 1.93 X 104 kg DE DO
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Width - 24 in 60 cm
Length - 48 in 120 cm
Create a table of conversion. Include final answers and solutions. Please see the example on the second pic
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CONVERSION OF UNITS
Example 2: The density of gold is 19.3 g/cm³.
What is the density in kg/m³?
Solution: G: 19.3 9
kg
cm
Click to add notes
English (Philippines)
19.3
Sms
8
2 (1kg) (12) ²
19.3 kg
1X10 X 10
.6.
m³
= 1.93 x 104 kg
Notes
19.3
TX 10-3 m3
DO
Kg = 19.3x0³49²
E
D
FI
H
Transcribed Image Text:III.
PROCEDURE
Part A: Rectangular Table
1. Using a meterstick or a ruler, measure the length and the width of the table and record them
in meters with the reading/measurement up to five significant figures. Record your data in the
data table in units of meters (m) in column (2), centimeters (cm) in column (3) and
millimeters (mm) in column (4). Use scientific notation any time the data or the calculation is
larger than 1000.
2. Calculate the area of the table top in m² cm² and mm² and enter it in the data table.
(Hint: Include the units. When you multiply the numbers, you also must multiply the units.)
Part B: Rectangular Block/Toy
and record your
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