(convernt into c++) Convert the following tail recursive function to iterative: int sequence1(int n) { if (n < 5) return n; else if (n % 2 == 0) else return sequence1(n/2); return sequence1 ((n-1)/2);
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c++ help
![(convernt into c++)
Convert the following tail recursive function to iterative:
int sequence1(int n)
{
}
if (n <5)
return n;
else if (n % 2
==
else
0)
return sequence1 (n/2);
return sequence1 ((n-1)/2);](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa15a3309-6b07-4866-b3be-9f0895e56cbb%2F2bf09702-2ab8-48f1-a8da-107562879292%2Ffrgn998_processed.jpeg&w=3840&q=75)
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- (Recursive Greatest Common Divisor) The greatest common divisor of integers x and y isthe largest integer that evenly divides both x and y. Write a recursive function gcd that returns thegreatest common divisor of x and y. The gcd of x and y is defined recursively as follows: If y is equalto 0, then gcd(x, y) is x; otherwise gcd(x, y) is gcd(y, x % y), where % is the remainder operator.(GREATEST COMMON DIVISOR) The greatest common divisor of integers x and y is the largest integer that evenly divides into both x and y. Write and test a recursive function gcd that returns the greatest common divisor of x and y. The gcd of x and y is defined recursively as follows: If y is equal to 0, then gcd (x, y) is x; otherwise, gcd (x, y) is gcd (y, x % y), where % is the remainder operator.(Using the programming language C, answer the following question) Write recursive C functions to do the following: Example: int summ(int n) returns the summation of integers from 0 to n. Here is the code. int summ(int n) { if(n < 0) return -1; if(n == 0) return 0; return n + summ(n - 1);} 1) If n is less than 0, the expression int bunnyEars(int n) returns -1; otherwise, it returns the number of ears for n bunnies. int factorial(int n) returns -1 if n is less than 0, otherwise returns the factorial of n. If n is greater than or equal to 0, the expression int fib(int n) returns -1; otherwise, it returns fib of n - 1 + fib of n - 2. (This will run quite slowly if you test it with more than roughly 50 digits.). int posPow(int base, int exp) returns -1 if exp is less than 0, otherwise returns base raised to the power exp. Write a main() that tests all the other functions thoroughly.
- Write a recursive function definition for the following function: int squares(int n); //Precondition: n >= 1 //Returns the sum of the squares of numbers 1 through n. For example, squares(3) returns 14 because 12 + 22 + 32 is 14.Consider the following function: void fun_with_recursion(int x) { printf("%i\n", x); fun_with_recursion(x + 1); } What will happen when this function is called by passing it the value 0?(Please provide photos so the code is easier to understand) Write a small C++ program that defines a recursive function GCD based on the model of the Lisp function (defun gcd (n m)"Returns the gcd of two numbers" (let ((dividend n) (divisor m) (remainder 1)) (while (/= remainder 0) (setq remainder (mod dividend divisor)) (setq dividend divisor) (setq divisor remainder)) dividend)) In the main function, write a loop (while or do) that repeats the following actions: ask the user to enter two numbers, compute their GCD and output it, until the user enters 0 for one of the numbers.
- C++ Help2 b) Explain what happens when the following recursive function is called with thevalue 4 as an argument:For glass box testing of a recursive function, you should test cases where: a) the function returns without a recursive call, ie using a base case b) the function makes exactly one recursive call c) the function makes more than one recursive call d) all of these
- c++ help please4. CodeW X For func X C Solved b Answer x+ https://codeworkou... ... [+) CodeWorkout X271: Recursion Programming Exercises: Minimum of array For function recursiveMin, write the missing part of the recursive call. This function should return the minimum element in an array of integers. You should assume that recursiveMin is initially called with startIndex = 0. Examples: recursiveMin({2, 4, 8}, 0) -> 2 Your Answer: 1 public int recursiveMin(int numbers[], int startIndex) { numbers.length - 1) { if (startIndex 2. return numbers[startIndex]; } else { return Math. min(numbers[startIndex], >); 5. { 1:11 AM 50°F Clear 12/4/2021lint power (int base, int exponent); Define the recursive function power() that when invoked returns baseonent Assume that exponent is an integer greater than or equal to 1. Hint: The recursion step would use the relationship basenent = base * baseonert- and the terminating condition occurs when exponent is equal to 1 because base' = base or when exponent is equal to o because base = 1.
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