continuous random variable X has probability density function J (x) me constant a = 1.1. What is the variance of X? Give your solution accurate to 4 decimal places. nswer: Check X lo otherwise 9

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A: f(x|θ)=c(θ)(θ2−x2)

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A:

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A: Introduction The probability density function of the random variable X is given.

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A:

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A: Solution

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A: Using rth order pdf.

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A: E(1Y) = ∫-∞∞1yf(y) dy

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A: µ = 62. P(X > 65.8) = 0.12

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A: The data shows the tensile strengths of the two treatments.