Here is the transcription of the provided image for educational purposes:---### Basic Electrical Equations- \( V = IR \)- \( I = \frac{V}{R} \)- \( R = \frac{V}{I} \)### Series Circuits- \( I_{\text{Tot}} = I_{1} = I_{2} \)- \( V_{\text{Tot}} = V_{1} + V_{2} \)- \( R_{\text{Tot}} = R_{1} + R_{2} \)### Parallel Circuits- \( I_{\text{Tot}} = I_{1} + I_{2} \)- \( V_{\text{Tot}} = V_{1} = V_{2} \)- \(\frac{1}{R_{\text{Tot}}} = \frac{1}{R_{1}} + \frac{1}{R_{2}} \)- \( R_{\text{Tot}} = \frac{R_{1} \cdot R_{2}}{R_{1} + R_{2}} \)---These equations summarize the fundamental principles of electrical circuits concerning Ohm's Law and the behavior of resistors in series and parallel configurations. **Finding the Total Equivalent Current in a Parallel Resistive Circuit**When two resistors are connected in parallel to a voltage source, the total equivalent resistance can be found using the formula:\[ \frac{1}{R_{\text{Tot}}} = \frac{1}{R_1} + \frac{1}{R_2} \]Given:- Resistor \( R_1 = 6 \, \Omega \)- Resistor \( R_2 = 12 \, \Omega \)- Voltage of the battery \( V = 9 \, \text{V} \) (labeled as BAT1 in the diagram)**Steps to find the total equivalent resistance \( R_{\text{Tot}} \):**1. Calculate the reciprocal of each resistance:\[ \frac{1}{R_1} = \frac{1}{6} \]\[ \frac{1}{R_2} = \frac{1}{12} \]2. Add these reciprocals together:\[ \frac{1}{R_{\text{Tot}}} = \frac{1}{6} + \frac{1}{12} \]\[ = \frac{2}{12} + \frac{1}{12} \]\[ = \frac{3}{12} \]\[ = \frac{1}{4} \]3. Take the reciprocal of the result to find \( R_{\text{Tot}} \):\[ R_{\text{Tot}} = 4 \, \Omega \]**Now, to find the total current \( I_{\text{Tot}} \), use Ohm's Law:**\[ I = \frac{V}{R} \]So,\[ I_{\text{Tot}} = \frac{9 \, \text{V}}{4 \, \Omega} \]\[ I_{\text{Tot}} = 2.25 \, \text{A} \]**Summary of Results:**- The total equivalent resistance \( R_{\text{Tot}} \) is \( 4 \, \Omega \).- The total current \( I_{\text{Tot}} \) flowing through the battery is \( 2.25 \, \text{A} \).**Diagram Explanation:**The provided circuit diagram illustrates the following components and their connections:1. A voltage source labeled \( \text{BAT1} \), providing \(

Series Connection of Resistors: When n no. of resistors are connected in series, their equivalent…

Continuing with the same setup as above, where you connect a 6Q resistor and a 12 Q resistor in parallel to a 9 V battery. Find the total equivalent current, ITot, flowing through the battery in Amperes. RTot ITot R1 R2 BAT1 12 Q 9 V

Continuing with the same setup as above, where you connect a 6Q resistor and a 12 Q resistor in parallel to a 9 V battery. Find the total equivalent current, ITot, flowing through the battery in Amperes. RTot ITot R1 R2 BAT1 12 Q 9 V

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Figure 22 (2 15:02 ww 12.0 V 120 V + 6.0 V 1122 ww ly 12.02 18 (2 1 of 1 Determine the currents Is. Is, and I in the figure Assume the internal resistance of each battery is 1.00 Express your answer using two significant figures. Enter your answers numerically separated by commes h.h.h Submit Part 8 V What is the terminal voltage of the 6.0-V battery? Express your answer using two significant figures VAX Submit Provide Feedback AZO Best An BA ? ? V A
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UPVOTE WILL BE GIVEN. PLEASE WRITE THE COMPLETE SOLUTIONS LEGIBLY. SOLVE IN 4 DECIMAL PLACES. BOX THE FINAL ANSWER.
Answer the questions in the attached photo, Thannk you
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