Continuing with the expression (x+7)², do the following. (a) By using the Distributive Property twice, show that this expression is equivalent to x² +14x+49. (b) Test the equivalency by finding the value of (x+7)² and x² +14x+49 when x = 3. (x+7)² x² +14x +49
Continuing with the expression (x+7)², do the following. (a) By using the Distributive Property twice, show that this expression is equivalent to x² +14x+49. (b) Test the equivalency by finding the value of (x+7)² and x² +14x+49 when x = 3. (x+7)² x² +14x +49
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:a) State if the two expressions are equivalent.
b) If the expressions are equivalent what were
their values when x=3?
3. Continuing with the expression (x+7), do the following.
(a) By using the Distributive Property twice, show
that this expression is equivalent to
x² +14x+49.
(b) Test the equivalency by finding the value of
(x+7) and x² +14x+49 when x = 3.
(x+7)²
x² +14x+49
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