Consumers with credit scores below 600 have a very difficult time getting approved for car or mortgage loans. Historically 27% of people had a credit score below 600. Due to the recent financial crisis, the federal government is concerned that this proportion has increased. To test this hypothesis, a random sample of 100 people was chosen. From this sample, 40 people had credit scores less than 600. Using a =0.10, complete parts a through c below Click here to view the first page of the standard normal table. Click here to view the second page of the standard normal table. a) Does this sample provide support for the government's concern that the proportion of people with credit scores below 600 has increased? Determine the null and alternative hypotheses. O A. Ho: 20.27 O B. Ho: x>0.27 H: n<0.27 H: s0.27 OC. Ho: =0.27 H: R#0.27 O D. H, as0.27 H x> 0.27
Consumers with credit scores below 600 have a very difficult time getting approved for car or mortgage loans. Historically 27% of people had a credit score below 600. Due to the recent financial crisis, the federal government is concerned that this proportion has increased. To test this hypothesis, a random sample of 100 people was chosen. From this sample, 40 people had credit scores less than 600. Using a =0.10, complete parts a through c below Click here to view the first page of the standard normal table. Click here to view the second page of the standard normal table. a) Does this sample provide support for the government's concern that the proportion of people with credit scores below 600 has increased? Determine the null and alternative hypotheses. O A. Ho: 20.27 O B. Ho: x>0.27 H: n<0.27 H: s0.27 OC. Ho: =0.27 H: R#0.27 O D. H, as0.27 H x> 0.27
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
A.) H0=? H1=?
B) critical value of the test statistic
C) calcuLate the test statistic
D) reject or do not reject based
on evidence of credit score level
E) p-value ?
Please answer all questions
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