Construct the molecular orbital diagram for He₂. He 0 0.5 1 O 1.5 02 1s Identify the bond order. He₂ o* 1s °1s He C 1s

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### Construct the Molecular Orbital Diagram for \( He_2 \)

To construct the molecular orbital (MO) diagram for the diatomic helium molecule \( He_2 \), follow these steps:

#### Diagram Explanation
- **Atomic Orbitals (AOs) from Each Helium Atom:** 
  - Each helium atom \( He \) contributes one \( 1s \) atomic orbital, represented at each side of the diagram.
  - These \( 1s \) orbitals are shown as squares labeled "1s" on both the left and right sides of the diagram.

- **Molecular Orbitals (MOs):**
  - When combining the two \( 1s \) atomic orbitals from each helium atom, two molecular orbitals are formed: a bonding orbital (\( \sigma_{1s} \)) and an antibonding orbital (\( \sigma^*_{1s} \)).
  - The bonding orbital (\( \sigma_{1s} \)) is at a lower energy level and is represented at the bottom center of the diagram.
  - The antibonding orbital (\( \sigma^*_{1s} \)) is at a higher energy level and is represented at the top center of the diagram.
  - The electron configuration is represented using boxes and arrows to show the electrons. He atom (1s²) will have two electrons represented by opposite-facing arrows in the box.

- **Electron Placement:**
  - Follow the given placeholders (dashed squares) for electrons in the molecular orbitals.
  - The Answer Bank provides arrows indicating electron spin. One shows a single upward arrow and the other a pair of arrows (one up and one down).

#### Bond Order Calculation
- **Identify the Bond Order:**
  - Bond order is calculated using the formula:
    \[
    \text{Bond Order} = \frac{(N_b - N_a)}{2}
    \]
    where \( N_b \) is the number of electrons in bonding orbitals and \( N_a \) is the number of electrons in antibonding orbitals.
  - For \( He_2 \), the electrons in \( \sigma_{1s} \) and \( \sigma^*_{1s} \) need to be summed up to identify the corresponding bond order.

Lastly, you can select the bond order from the given options:
- \( \circ \) 0
- \(
Transcribed Image Text:### Construct the Molecular Orbital Diagram for \( He_2 \) To construct the molecular orbital (MO) diagram for the diatomic helium molecule \( He_2 \), follow these steps: #### Diagram Explanation - **Atomic Orbitals (AOs) from Each Helium Atom:** - Each helium atom \( He \) contributes one \( 1s \) atomic orbital, represented at each side of the diagram. - These \( 1s \) orbitals are shown as squares labeled "1s" on both the left and right sides of the diagram. - **Molecular Orbitals (MOs):** - When combining the two \( 1s \) atomic orbitals from each helium atom, two molecular orbitals are formed: a bonding orbital (\( \sigma_{1s} \)) and an antibonding orbital (\( \sigma^*_{1s} \)). - The bonding orbital (\( \sigma_{1s} \)) is at a lower energy level and is represented at the bottom center of the diagram. - The antibonding orbital (\( \sigma^*_{1s} \)) is at a higher energy level and is represented at the top center of the diagram. - The electron configuration is represented using boxes and arrows to show the electrons. He atom (1s²) will have two electrons represented by opposite-facing arrows in the box. - **Electron Placement:** - Follow the given placeholders (dashed squares) for electrons in the molecular orbitals. - The Answer Bank provides arrows indicating electron spin. One shows a single upward arrow and the other a pair of arrows (one up and one down). #### Bond Order Calculation - **Identify the Bond Order:** - Bond order is calculated using the formula: \[ \text{Bond Order} = \frac{(N_b - N_a)}{2} \] where \( N_b \) is the number of electrons in bonding orbitals and \( N_a \) is the number of electrons in antibonding orbitals. - For \( He_2 \), the electrons in \( \sigma_{1s} \) and \( \sigma^*_{1s} \) need to be summed up to identify the corresponding bond order. Lastly, you can select the bond order from the given options: - \( \circ \) 0 - \(
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