Construct the indicated confidence interval for the population mean u using the t-distribution. Assume the population is normally distributed. c= 0.99, x 13.8, s=4.0, n=7 The 99% confidence interval using a t-distribution is (OD. (Round to one decimal place as needed.)

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**Constructing a Confidence Interval for a Population Mean**

When given the task to construct a confidence interval for the population mean \(\mu\) using the t-distribution, it's essential to assume the population is normally distributed. Here's how to construct a 99% confidence interval with the given data:

### Given Values:
- Confidence level (\(c\)): 0.99
- Sample mean (\(\bar{x}\)): 13.8
- Sample standard deviation (\(s\)): 4.0
- Sample size (\(n\)): 7

### Objective:
To find the 99% confidence interval using a t-distribution.

### Steps to Construct the Interval:
1. **Identify the t-score:**
   - Use a t-distribution table or calculator to find the t-score that corresponds to a 99% confidence level with \(n-1\) degrees of freedom (in this case, 6 degrees of freedom).

2. **Calculate the Standard Error (SE):**
   \[ SE = \frac{s}{\sqrt{n}} = \frac{4.0}{\sqrt{7}} \]

3. **Construct the Confidence Interval:**
   \[
   \text{Confidence Interval} = \bar{x} \pm (t \times SE)
   \]
   Where \(t\) is the t-score obtained from the t-distribution.

4. **Round to One Decimal Place:**
   - Ensure the final confidence interval is rounded to one decimal place as specified.

The final confidence interval will look like \(( \_\_.\_ , \_\_.\_ )\), providing a range within which the population mean is likely to fall with 99% confidence.

### Note:
- It is critical to use the appropriate t-score and SE to ensure accuracy.
- Computers or statistical software can help automate these calculations and minimize errors.
Transcribed Image Text:**Constructing a Confidence Interval for a Population Mean** When given the task to construct a confidence interval for the population mean \(\mu\) using the t-distribution, it's essential to assume the population is normally distributed. Here's how to construct a 99% confidence interval with the given data: ### Given Values: - Confidence level (\(c\)): 0.99 - Sample mean (\(\bar{x}\)): 13.8 - Sample standard deviation (\(s\)): 4.0 - Sample size (\(n\)): 7 ### Objective: To find the 99% confidence interval using a t-distribution. ### Steps to Construct the Interval: 1. **Identify the t-score:** - Use a t-distribution table or calculator to find the t-score that corresponds to a 99% confidence level with \(n-1\) degrees of freedom (in this case, 6 degrees of freedom). 2. **Calculate the Standard Error (SE):** \[ SE = \frac{s}{\sqrt{n}} = \frac{4.0}{\sqrt{7}} \] 3. **Construct the Confidence Interval:** \[ \text{Confidence Interval} = \bar{x} \pm (t \times SE) \] Where \(t\) is the t-score obtained from the t-distribution. 4. **Round to One Decimal Place:** - Ensure the final confidence interval is rounded to one decimal place as specified. The final confidence interval will look like \(( \_\_.\_ , \_\_.\_ )\), providing a range within which the population mean is likely to fall with 99% confidence. ### Note: - It is critical to use the appropriate t-score and SE to ensure accuracy. - Computers or statistical software can help automate these calculations and minimize errors.
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