Construct the 99% confidence interval estimate of the population proportion p if the sample size is n = 300 and the number of successes in the sample is = 221. < p<
Construct the 99% confidence interval estimate of the population proportion p if the sample size is n = 300 and the number of successes in the sample is = 221. < p<
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![**Constructing a 99% Confidence Interval for a Population Proportion**
To construct the 99% confidence interval estimate for the population proportion \( p \), we start with the given data:
- Sample size (\( n \)) = 300
- Number of successes (\( x \)) = 221
Next, we follow these steps:
1. Calculate the sample proportion (\( \hat{p} \)).
\[
\hat{p} = \frac{x}{n} = \frac{221}{300}
\]
2. Determine the standard error (SE) of the sample proportion.
\[
SE = \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}
\]
3. Identify the z-score corresponding to the 99% confidence level. For a 99% confidence interval, this z-score is typically 2.576.
4. Calculate the margin of error (ME).
\[
ME = z \times SE
\]
5. Finally, construct the confidence interval.
\[
\hat{p} - ME < p < \hat{p} + ME
\]
The blank areas in the image indicate where the calculated lower and upper bounds of the confidence interval will be input. These calculations provide the range within which the true population proportion \( p \) lies with 99% confidence.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fab42d873-9f18-4f4e-9eaf-77750f86fa7d%2F01b169c1-81b2-44e5-ae51-2fb9a9b76c5c%2Fdn4noen_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Constructing a 99% Confidence Interval for a Population Proportion**
To construct the 99% confidence interval estimate for the population proportion \( p \), we start with the given data:
- Sample size (\( n \)) = 300
- Number of successes (\( x \)) = 221
Next, we follow these steps:
1. Calculate the sample proportion (\( \hat{p} \)).
\[
\hat{p} = \frac{x}{n} = \frac{221}{300}
\]
2. Determine the standard error (SE) of the sample proportion.
\[
SE = \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}
\]
3. Identify the z-score corresponding to the 99% confidence level. For a 99% confidence interval, this z-score is typically 2.576.
4. Calculate the margin of error (ME).
\[
ME = z \times SE
\]
5. Finally, construct the confidence interval.
\[
\hat{p} - ME < p < \hat{p} + ME
\]
The blank areas in the image indicate where the calculated lower and upper bounds of the confidence interval will be input. These calculations provide the range within which the true population proportion \( p \) lies with 99% confidence.
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