Construct a​ 99% confidence interval for the population proportion. Interpret the results

Q: regular users of e-cigarettes. Because e-cigarette use is relatively new, there is a need to obtain…

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Q: Global Warming In April of 2014, a Gallup Poll of 1048 U.S. adults found that 25% of the respondents…

A: From the provided information, Sample size (n) = 1048 25% of the respondents were skeptical that…

Q: 132,000 189,000 270,000 324,800 269,000 340,000 222,000 135,000 169,900 310,000 142,900 86,000…

A: Given information: x 132000 324800 222000 310000 285000 189000 269000 135000…

Q: You are given the sample mean and the population standard deviation. Use this information to…

A: We have given that , Mean = 145 , SD = 18.8 , Sampl size = 55 , We have to find, 90% of Confidence…

Q: pretty sure is in your interval? 1. 90% of the sample data. II. 90% of all sample proportions. III.…

A: Construct 90% Confidence interval for population proportion p

Q: A professor is interested in how attendance influences grades her class. She goes through her…

A: 1) Given Data :  We will calculate the point estimate which will be the mean of this sample data,…

Q: In a survey of 2244 adults in a recent year, 1242 say they have made a New Year's resolution.…

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Q: 405 (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E=D…

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Q: 32, 35, 38, 32, 30, 32, 33, 29, 38, 35, 3,31 Q5. Lower ve Q6. Upper value= Consider the sample:…

A: The sample observation values are given as: 32,35,38,32,30,32,33,29,38,35,3,31.

Q: for to the data set of 20 randomly selected presidents given below. Treat the data as a sample and…

A: The confidence interval formula to estimate the true population proportion is defined as…

Q: 9s

A: Margin of error =E =5%=0.05 90% confidence level

Q: In a survey of 3352 adults, 1435 say they have started paying bills online in the last year.…

A: From the provided information, Sample size (n) = 3352 From which 1435 say they have started paying…

Q: 14. Direct Mail A survey shows that 51% of adults prefer to receive advertisements through the mail.…

A: Given percent of adults prefer to receive advertisements through the mail=51%Margin of error(E)=5.2%

Q: The next five questions refer to the following scenario: 10 sample mean x • sample sizen = 100…

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Q: Using the dot plot from your link, count how many of the data values lie within the confidence…

A: Using the information given in the first image, we will answer the questions given in the second…

Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…

A: It is given that sample size (n) is 986 and x is 522.

Q: For the same sample statistics, which level of confidence would produce the widest confidence…

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Q: Use the sample data and confidence level given below to complete parts  (b)   A research institute…

A: Margin of error can be calculated as shown below.

Q: Exercise 2 Problem 12 12 Information. You are given the data in the table on the right 21 19…

A: Solution Here is two different questions I am solving exercise 2

Q: King Salmon in the Kenai River. Deion works for Alaska Fish and Game. They would like to know the…

A: Solution-: We want to find, (a) 95% C.I. (b) Margin of error=? (c) Interpret 95% C.I.

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

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Q: In a survey of 2587 adults in a recent​ year, 1241 say they have made a New​ Year's resolution.…

A: From the provided information Sample size (n) = 2587 1241 say they have made a New​ Year's…

Q: In a survey of 2882 adults,1401 say they have started paying bills online in the last year.…

A: Sample size (n) = 2882 From which 1401 say they have started paying bills online in the last year.…

Q: Translate the statement into a confidence interval. Approximate the level of confidence.  In a…

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Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: Given,n=130X=69p^=Xnp^=69130=0.5311-p^=1-0.531=0.469α=1-0.99=0.01α2=0.005Z0.005=2.576     (from…

Q: In a survey of 2271 ​adults, 714 say they believe in UFOs.   Construct a 99% confidence interval for…

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Q: 10. You take a sample of 200 University of Maryland students and find that 80 them think that the…

A: 10. It was stated that a sample of 200 Maryland University students are taken. It was given that…

Q: In a survey of 2969 ​adults, 1401 say they have started paying bills online in the last year.…

A:

Q: vey asked 1309 people wnether they performed any volunteer work during the past year. A of 518…

A: Given that  Sample size n =1309 Favorable cases x =518 Sample proportion p^=x/n

Q: A magazine provided results from a poll of 2000 adults who were asked to identify their favorite…

A: It is given that among the 2000 respondents, 14% chose chocolate pie, and the margin of error was…

Q: Use the confidence interval to find the margin of error and the sample mean. (0.072,0.210) The…

A: Given Confidence of interval (0.072,0.210)

Q: 6. Explain what this confidence interval means to your boss, who has never taken a statistics class.…

A: What is confidence interval and explain it to non statistics person.

Q: In general, when you increase the confidence level for a confidence interval using the same sample…

A: As confidence level increases critical value is going to increase .  Here they given sample…

Q: Briefly discuss the meaning of a 95% confidence interval and a 99% confidence interval and how they…

A: A confidence interval is a range of values that quantifies the uncertainty or level of confidence…

Q: Please no written by hand The following table compares the completion percentage and interception…

A: To construct the 98% confidence interval for the slope, we need to perform linear regression…

Q: Determine whether the statement below makes sense or does not make sense. Explain clearly.

A: Here given , Based on our sample, the 95% confidence interval for the mean amount of television…

Q: Use the information about each of the following samples to compute the confidence interval to…

A: Since you have posted a question with multiple sub parts, we will provide the solution only to the…

Q: A survey was conducted that asked 1019 people how many books they had read in the past year. Results…

A: X-bar=10.3 S=16.6 Sample size=1019 We need to construct 90% confidence interval