Construct a DFA or NFA with as few states as you can for the language {w w € {0, 1}*; every second and every third position of w is a 1} [Explanation: So, there are 2 requirements for a string to be in L, every even position must be 1. And every third position (3rd, 6th, 9th, etc.) must also be 1. For example 110111 L because 3rd position is not 1. 011101 € L because all 2nd, 3rd, 4th, 6th positions are 1 as required.] P1 L =
Construct a DFA or NFA with as few states as you can for the language {w w € {0, 1}*; every second and every third position of w is a 1} [Explanation: So, there are 2 requirements for a string to be in L, every even position must be 1. And every third position (3rd, 6th, 9th, etc.) must also be 1. For example 110111 L because 3rd position is not 1. 011101 € L because all 2nd, 3rd, 4th, 6th positions are 1 as required.] P1 L =
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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PLEASE DONT USE CHATGPT. USE PENCIL AND PAPER, TAKE A PHOTO AND SEND ME.
![Construct a DFA or NFA with as few states as you can for the language
L = {w we {0, 1}*; every second and every third position of w is a 1}
[Explanation: So, there are 2 requirements for a string to be in L, every even position must be 1.
And every third position (3rd, 6th, 9th, etc.) must also be 1. For example 110111 L because 3rd
position is not 1. 011101 € L because all 2nd, 3rd, 4th, 6th positions are 1 as required.]
P1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F204c9e4b-3bf7-43a8-a323-d786ca682c55%2F97a40c66-6d83-450c-8222-b391793ae2ff%2F8wh8hde_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Construct a DFA or NFA with as few states as you can for the language
L = {w we {0, 1}*; every second and every third position of w is a 1}
[Explanation: So, there are 2 requirements for a string to be in L, every even position must be 1.
And every third position (3rd, 6th, 9th, etc.) must also be 1. For example 110111 L because 3rd
position is not 1. 011101 € L because all 2nd, 3rd, 4th, 6th positions are 1 as required.]
P1
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