Constants Imagine the Carnot heat engine represented by the p vs. V diagram given in (Figure 1). Part D Because of this difference in entropy change, the net entropy change of the entire system is isothermal expansion. during a real Complete the sentence above. • View Available Hint(s) O positive Figure 1 of 1 O negative O zero Submit Isothermal Part E Complete previous part(s) Adiabatic Part F Complete previous part(s) Adiabatic Part G Complete previous part(s) Isothermal →V

Constants Imagine the Carnot heat engine represented by the p vs. V diagram given in (Figure 1). Part D Because of this difference in entropy change, the net entropy change of the entire system is isothermal expansion. during a real Complete the sentence above. • View Available Hint(s) O positive Figure 1 of 1 O negative O zero Submit Isothermal Part E Complete previous part(s) Adiabatic Part F Complete previous part(s) Adiabatic Part G Complete previous part(s) Isothermal →V

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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The pV diagram in (Figure 1) shows the cycle followed by the gas in an ideal-gas refrigerator whose coefficient of performance is 1.5. The work done by the system during two adiabatic processes is shown. Figure P 4 Adiabats 1 of 1 > W₁ = -119 J W, = 79 J V ▼ ✓ Correct Part F What is Win for one cycle of this heat engine? Express your answer with the appropriate units. View Available Hint(s) Win = 119 μÅ Submit Previous Answers Request Answer Part G Complete previous part(s) J X Incorrect; Try Again; One attempt remaining Part H Complete previous part(s) Provide Feedback ?
Can you please answer the follwing question, I did the right work but it seems that is not the right answer.
A heat engine using a diatomic ideal gas goes through the following closed cycle: • Isothermal compression until the volume is halved. • Isobaric expansion until the volume is restored to its initial value. • Isochoric cooling until the pressure is restored to its initial value. Part A What is the thermal efficiency of this heat engine? IVE ΑΣΦ n=0.088 Submit Part B Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Submit What is the thermal efficiency a Carnot engine operating between the highest and lowest temperatures reached by this engine? ΠΫΠΙ ΑΣΦ Carnot = 0.5 ? Previous Answers Request Answer % X Incorrect; Try Again; 5 attempts remaining ? %
Problem 1 A 0.20 kg/s of air are compressed isothermally from P,= 100 kPa and V,= 0.15 m3/s to P,= 700 kPa. Determine: The work in kW and the change in entropy in kJ/s-K for (a) closed or non-flow process and (b) open or steady flow process with initial and final velocity of v, = 15 m/s and v, = 60 m/s, respectively.
The attached files have 3 parts, i am gonna type the last 2 parts as wee: Calculate the change in entropy for the aluminium cup(in J/K) Calculate the total change in entropy for entire system (in J/K)
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1 mole of monatomic ideal gas initially at a volume of 2 L and a pressure of 10 atm is processed through a cycle where it first expands isothermally and reversibly to a final pressure of 2.5 atm, is then reversibly and isochorically cooled to a final temperature of 97.32 K, and then is reversibly and adiabatically compressed back to the initial state. 1. Determine the total work for the cycle 2. Determine change in internal energy for the cycle
P-1 Please I need help with this question needed very clearly and step by step explanation and NEEDED ONLY TYPED SOLUTIONS PLEASE NO HANDWRITTEN please, will be really appreciated for your help. NEEDED ONLY TYPED SOLUTIONS
Can you answer a b and c