### Applied Physics: Motion on an Incline**Problem Statement:**A horizontal force \( F_p = 150 \, \text{N} \) pushes a block weighing 18 kg up a 5.0 m distance along an incline angled at \( 32^\circ \). The coefficient of kinetic friction (\( \mu_k \)) is 0.13.**Diagram Description:**- **Block:** Depicted as a rectangle labeled "18 kg", positioned on an inclined plane. - **Incline:** Makes a \( 32^\circ \) angle with the horizontal.- **Force \( F_p \):** Represented by an arrow pointing parallel to the plane surface, indicating a force of 150 N.**Key Concept:**In solving problems involving motion across an inclined plane, the work-energy principle is useful. This principle involves calculating the net work done, accounting for gravitational forces, applied forces, and frictional forces.Make sure to consider both the component of gravitational force along the plane and the frictional force opposing the motion. Use trigonometry to resolve forces and the work-energy theorem to analyze energy transformations. ## Part E**Question:** What is the speed of the block (assume that it is zero initially) after this displacement?**Instructions:** Express your answer to two significant figures and include the appropriate units.**Answer Input Section:**- Input Box with Placeholder: - First Box: `1.4` - Units Selection: - `m/s`**Interface Buttons:**- Submit Button- Navigation Links: - `Previous Answers` - `Request Answer` **Feedback Section:**- Message: **Incorrect; Try Again; 3 attempts remaining** This section is aimed to test your understanding of kinematic problems by calculating the speed of a block, given its initial speed is zero.

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Constants I Periodic Table The horizontal force Fp = 150 N force pushes the block of 5.0 m up along the 32° incline? A coefficient of friction Fp= 18 kg 150 N 32° plik = 0.13. [Hint: Work-energy involves net work done.]

Constants I Periodic Table The horizontal force Fp = 150 N force pushes the block of 5.0 m up along the 32° incline? A coefficient of friction Fp= 18 kg 150 N 32° plik = 0.13. [Hint: Work-energy involves net work done.]

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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### Applied Physics: Motion on an Incline

**Problem Statement:**
A horizontal force \( F_p = 150 \, \text{N} \) pushes a block weighing 18 kg up a 5.0 m distance along an incline angled at \( 32^\circ \). The coefficient of kinetic friction (\( \mu_k \)) is 0.13.

**Diagram Description:**
- **Block:** Depicted as a rectangle labeled "18 kg", positioned on an inclined plane.
- **Incline:** Makes a \( 32^\circ \) angle with the horizontal.
- **Force \( F_p \):** Represented by an arrow pointing parallel to the plane surface, indicating a force of 150 N.

**Key Concept:**
In solving problems involving motion across an inclined plane, the work-energy principle is useful. This principle involves calculating the net work done, accounting for gravitational forces, applied forces, and frictional forces.

Make sure to consider both the component of gravitational force along the plane and the frictional force opposing the motion. Use trigonometry to resolve forces and the work-energy theorem to analyze energy transformations.

## Part E

**Question:**
What is the speed of the block (assume that it is zero initially) after this displacement?

**Instructions:**
Express your answer to two significant figures and include the appropriate units.

**Answer Input Section:**

- Input Box with Placeholder:
- First Box: `1.4`
- Units Selection:
- `m/s`

**Interface Buttons:**

- Submit Button
- Navigation Links:
- `Previous Answers`
- `Request Answer`

**Feedback Section:**

- Message: **Incorrect; Try Again; 3 attempts remaining**

This section is aimed to test your understanding of kinematic problems by calculating the speed of a block, given its initial speed is zero.

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