Constants An iron block with mass mg sides down a trictionless hill of height H. At the base of the hill,it collides with and sticks to a magnet with mass mu • Part A What is the speed v of the block and magnet immediately after the collision? > View Available Hint(s) O v = ( 2gH Ov- ( ) 2gH O- ( 29H Submit • Part B Now assume that the two masses continue to move at the speed e trom Part A until they encounter a rough surface. The coefficient of triction between the masses and the surtace is . If the blocks come to rest after a distance s, which of the following equations would you use to finds? View Available Hints) o ma gH = umags gH = umugs gH - p(ma + mM)gs o m gH = -µ(mg + mu)gs gH - p(ma + mM)g

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Chapter1: Units, Trigonometry. And Vectors
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Constants
An iron block with mass mp slides down a frictionless hill of height H. At the base of the hill, it collides with and
sticks to a magnet with mass mM.
Part A
What is the speed v of the block and magnet immediately after the collision?
• View Available Hint(s)
mg+mM
O v=
V29H
mB
O v=
V29H
mB+mM
O v=
mB
V29H
тм
mB+mM
O v =
2gH
mB
mB
O v=
2gH
Submit
Part B
Now assume that the two masses continue to move at the speed
from Part A until they encounter
rough surface. The coefficient of friction between the masses and the surface is u. If the blocks come to rest after a distance s, which of the following equations would
you use to find s?
• View Available Hint(s)
(тв)?
gH = µmBgs
mB+mM
(тв)?
gH = µmMgs
mB+mM
(тв)?
gH = µ(mB + mM)gs
mB+mM
(тв)?
gH = -µ(mB + MM)gs
mB+mM
(mB)?
gH = µ(mB + mm)g
mB+mM
Transcribed Image Text:Constants An iron block with mass mp slides down a frictionless hill of height H. At the base of the hill, it collides with and sticks to a magnet with mass mM. Part A What is the speed v of the block and magnet immediately after the collision? • View Available Hint(s) mg+mM O v= V29H mB O v= V29H mB+mM O v= mB V29H тм mB+mM O v = 2gH mB mB O v= 2gH Submit Part B Now assume that the two masses continue to move at the speed from Part A until they encounter rough surface. The coefficient of friction between the masses and the surface is u. If the blocks come to rest after a distance s, which of the following equations would you use to find s? • View Available Hint(s) (тв)? gH = µmBgs mB+mM (тв)? gH = µmMgs mB+mM (тв)? gH = µ(mB + mM)gs mB+mM (тв)? gH = -µ(mB + MM)gs mB+mM (mB)? gH = µ(mB + mm)g mB+mM
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