Constants An iron block with mass mg sides down a trictionless hill of height H. At the base of the hill,it collides with and sticks to a magnet with mass mu • Part A What is the speed v of the block and magnet immediately after the collision? > View Available Hint(s) O v = ( 2gH Ov- ( ) 2gH O- ( 29H Submit • Part B Now assume that the two masses continue to move at the speed e trom Part A until they encounter a rough surface. The coefficient of triction between the masses and the surtace is . If the blocks come to rest after a distance s, which of the following equations would you use to finds? View Available Hints) o ma gH = umags gH = umugs gH - p(ma + mM)gs o m gH = -µ(mg + mu)gs gH - p(ma + mM)g
Constants An iron block with mass mg sides down a trictionless hill of height H. At the base of the hill,it collides with and sticks to a magnet with mass mu • Part A What is the speed v of the block and magnet immediately after the collision? > View Available Hint(s) O v = ( 2gH Ov- ( ) 2gH O- ( 29H Submit • Part B Now assume that the two masses continue to move at the speed e trom Part A until they encounter a rough surface. The coefficient of triction between the masses and the surtace is . If the blocks come to rest after a distance s, which of the following equations would you use to finds? View Available Hints) o ma gH = umags gH = umugs gH - p(ma + mM)gs o m gH = -µ(mg + mu)gs gH - p(ma + mM)g
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![Constants
An iron block with mass mp slides down a frictionless hill of height H. At the base of the hill, it collides with and
sticks to a magnet with mass mM.
Part A
What is the speed v of the block and magnet immediately after the collision?
• View Available Hint(s)
mg+mM
O v=
V29H
mB
O v=
V29H
mB+mM
O v=
mB
V29H
тм
mB+mM
O v =
2gH
mB
mB
O v=
2gH
Submit
Part B
Now assume that the two masses continue to move at the speed
from Part A until they encounter
rough surface. The coefficient of friction between the masses and the surface is u. If the blocks come to rest after a distance s, which of the following equations would
you use to find s?
• View Available Hint(s)
(тв)?
gH = µmBgs
mB+mM
(тв)?
gH = µmMgs
mB+mM
(тв)?
gH = µ(mB + mM)gs
mB+mM
(тв)?
gH = -µ(mB + MM)gs
mB+mM
(mB)?
gH = µ(mB + mm)g
mB+mM](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1031243a-2683-4bed-939c-b2637ff093c6%2Fbb347358-f8be-4e65-b796-97cb1ddc1c40%2F97qjsig_processed.png&w=3840&q=75)
Transcribed Image Text:Constants
An iron block with mass mp slides down a frictionless hill of height H. At the base of the hill, it collides with and
sticks to a magnet with mass mM.
Part A
What is the speed v of the block and magnet immediately after the collision?
• View Available Hint(s)
mg+mM
O v=
V29H
mB
O v=
V29H
mB+mM
O v=
mB
V29H
тм
mB+mM
O v =
2gH
mB
mB
O v=
2gH
Submit
Part B
Now assume that the two masses continue to move at the speed
from Part A until they encounter
rough surface. The coefficient of friction between the masses and the surface is u. If the blocks come to rest after a distance s, which of the following equations would
you use to find s?
• View Available Hint(s)
(тв)?
gH = µmBgs
mB+mM
(тв)?
gH = µmMgs
mB+mM
(тв)?
gH = µ(mB + mM)gs
mB+mM
(тв)?
gH = -µ(mB + MM)gs
mB+mM
(mB)?
gH = µ(mB + mm)g
mB+mM
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