Constants An iron block with mass mg sides down a trictionless hill of height H. At the base of the hill,it collides with and sticks to a magnet with mass mu • Part A What is the speed v of the block and magnet immediately after the collision? > View Available Hint(s) O v = ( 2gH Ov- ( ) 2gH O- ( 29H Submit • Part B Now assume that the two masses continue to move at the speed e trom Part A until they encounter a rough surface. The coefficient of triction between the masses and the surtace is . If the blocks come to rest after a distance s, which of the following equations would you use to finds? View Available Hints) o ma gH = umags gH = umugs gH - p(ma + mM)gs o m gH = -µ(mg + mu)gs gH - p(ma + mM)g
Constants An iron block with mass mg sides down a trictionless hill of height H. At the base of the hill,it collides with and sticks to a magnet with mass mu • Part A What is the speed v of the block and magnet immediately after the collision? > View Available Hint(s) O v = ( 2gH Ov- ( ) 2gH O- ( 29H Submit • Part B Now assume that the two masses continue to move at the speed e trom Part A until they encounter a rough surface. The coefficient of triction between the masses and the surtace is . If the blocks come to rest after a distance s, which of the following equations would you use to finds? View Available Hints) o ma gH = umags gH = umugs gH - p(ma + mM)gs o m gH = -µ(mg + mu)gs gH - p(ma + mM)g
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Title: Physics Problem: Motion and Collision**
**Problem Statement:**
An iron block with mass \( m_3 \) slides down a frictionless hill of height \( H \). At the base of the hill, it collides with and sticks to a magnet with mass \( m_4 \).
---
### Part A
**Question:**
What is the speed \( v \) of the block and magnet immediately after the collision?
**Answer Options:**
- \( v = \left( \frac{m_3 + m_4}{m_3} \right) \sqrt{2gH} \)
- \( v = \frac{m_4}{m_3} \sqrt{2gH} \)
- \( v = \frac{m_3}{m_4} \sqrt{2gH} \)
- \( v = \left( \frac{m_3 - m_4}{m_3} \right) 2gH \)
- \( v = \left( \frac{m_3}{m_4} \right) 2gH \)
[Submit]
---
### Part B
**Question:**
Now assume that the two masses continue to move at the speed \( v \) from Part A until they encounter a rough surface. The coefficient of friction between the masses and the surface is \( \mu \). If the blocks come to rest after a distance \( s \), which of the following equations would you use to find \( s \)?
**Answer Options:**
- \( \left( \frac{m_3}{m_4} \right) v^2 = \mu m_3gs \)
- \( \left( \frac{m_3}{m_4} \right) gH = \mu m_4gs \)
- \( \left( \frac{m_3 + m_4}{m_4} \right) gH = \mu m_3gs \)
- \( \left( \frac{m_3 - m_4}{m_3} \right) gH = \mu (m_3 + m_4) gs \)
- \( \left( \frac{m_3}{m_4} \right) gH = \mu (m_3 + m_4) gs \)
[Submit]
**Constants:**
Relevant constants](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1031243a-2683-4bed-939c-b2637ff093c6%2Fbb347358-f8be-4e65-b796-97cb1ddc1c40%2F97qjsig_processed.png&w=3840&q=75)
Transcribed Image Text:**Title: Physics Problem: Motion and Collision**
**Problem Statement:**
An iron block with mass \( m_3 \) slides down a frictionless hill of height \( H \). At the base of the hill, it collides with and sticks to a magnet with mass \( m_4 \).
---
### Part A
**Question:**
What is the speed \( v \) of the block and magnet immediately after the collision?
**Answer Options:**
- \( v = \left( \frac{m_3 + m_4}{m_3} \right) \sqrt{2gH} \)
- \( v = \frac{m_4}{m_3} \sqrt{2gH} \)
- \( v = \frac{m_3}{m_4} \sqrt{2gH} \)
- \( v = \left( \frac{m_3 - m_4}{m_3} \right) 2gH \)
- \( v = \left( \frac{m_3}{m_4} \right) 2gH \)
[Submit]
---
### Part B
**Question:**
Now assume that the two masses continue to move at the speed \( v \) from Part A until they encounter a rough surface. The coefficient of friction between the masses and the surface is \( \mu \). If the blocks come to rest after a distance \( s \), which of the following equations would you use to find \( s \)?
**Answer Options:**
- \( \left( \frac{m_3}{m_4} \right) v^2 = \mu m_3gs \)
- \( \left( \frac{m_3}{m_4} \right) gH = \mu m_4gs \)
- \( \left( \frac{m_3 + m_4}{m_4} \right) gH = \mu m_3gs \)
- \( \left( \frac{m_3 - m_4}{m_3} \right) gH = \mu (m_3 + m_4) gs \)
- \( \left( \frac{m_3}{m_4} \right) gH = \mu (m_3 + m_4) gs \)
[Submit]
**Constants:**
Relevant constants
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