Answered: Constants A deep-sea diver is suspended…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A deep-sea diver is suspended beneath the surface of Loch Ness by a cable of length h= 100 mthat is attached to a boat on the surface (Figure 1). The diver and his suit have a total mass of m= 120 kgand a volume of V= 7.70×10⁻²m3. The cable has a diameter of 1.85 cmand a linear mass density of μ= 1.19 kg/m. The diver thinks he sees something moving in the murky depths and jerks the end of the cable back and forth to send transverse waves up the cable as a signal to his companions in the boat.

Please help. I got stucked.

Constants
A deep-sea diver is suspended beneath the surface of
Loch Ness by a cable of length h = 100 m that is
attached to a boat on the surface (Figure 1). The diver
and his suit have a total mass of m 120 kg and a
volume of V 7.70x10-2 m3 .The cable has a diameter
of 1.85 cm and a linear mass density of u 1.19 kg/m
The diver thinks he sees something moving in the murky
depths and jerks the end of the cable back and forth to
send transverse waves up the cable as a signal to his
companions in the boat
Correct
Part B
Calculate the tension in the cable a distance x above the diver. The buoyant force on the cable must be included in your calculation.
Express your answer in terms of the variables i, p.ater, d, x, m, V, and appropriate constants.
VO
A
?
Vx Vx
X
X.10
Xb
b
X
F(a)(mx)g-(V+nd'x)Pwater
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Figure
1 of 1
Part C
J
The speed of transverse waves on the cable is given by v =
find the time required for the first signal to reach the surface.
The speed therefore varies along the cable, since the tension is not constant. (This expression neglects the damping force that the water exerts on the moving cable.) Integrate to
100 m
AED
S
= 120 kg
m
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