Constant operating speed characteristics; H = 55 – 460v² and ng = 8,2v – 130v³ Water is drawn from a pond by means of a centrifugal pump given with equations, and it is pumped into a 25 m high open water reservoir with a flow rate of 0.15 m^3/s. The pipe length used during this process is 130m and the continuous load coefficient on the pipe is given as 0.024. Since the local load losses in the system are neglected; (p3su= 998 kg/m³)
Constant operating speed characteristics; H = 55 – 460v² and ng = 8,2v – 130v³ Water is drawn from a pond by means of a centrifugal pump given with equations, and it is pumped into a 25 m high open water reservoir with a flow rate of 0.15 m^3/s. The pipe length used during this process is 130m and the continuous load coefficient on the pipe is given as 0.024. Since the local load losses in the system are neglected; (p3su= 998 kg/m³)
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
![P1
v?
P2
+ d2 29
pg
L V²
+ zz + h¢arbin, + hx,toplam hksūrekli= f.5:2a
+ z1 + hpompa,f
pg
pg¥H
Wmit =
hK.yerel =Kr, hg.toplam= hx,sûrekli + hg,yerel
Nsp
%3D
Протра
(gH)3/4
一()-)(图)第-(m)(合)
1/2
wWmil
Nst =
p1/2(gH)5/4
Wmil,B _ PB (WB
(DB
DA
WB (DR
HB
WB
%3D
%3D
HA
Wmil = PgHỳNturbin
wa DA
VA
Wmil = prwv(V; – rw)(1 – cosß)
Constant operating speed characteristics; H = 55 – 460v² and ng = 8,2v – 130V3
Water is drawn from a pond by means of a centrifugal pump given with
equations, and it is pumped into a 25 m high open water reservoir with a flow
rate of 0.15 m^3/s. The pipe length used during this process is 130 m and the
continuous load coefficient on the pipe is given as 0.024. Since the local load
losses in the system are neglected; (psu= 998 kg/m³)
a) Find the diameter of the discharge pipe
b) Find the power of the pump.
c) Find the manometric head of the pump.
0,12 m
77 kW
0,10 m
83 kW
54,27 m
55,21 m
0,29 m
88 kW
O 0,20 m
O 79 kW
44,65 m
61,87 m
0,30 m
91 kW
41,54 m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8888f91d-5ac3-40af-962e-3df5f2818599%2Ff84f4068-3661-4a2b-8960-ecedea3fd381%2Fb12y4j_processed.png&w=3840&q=75)
Transcribed Image Text:P1
v?
P2
+ d2 29
pg
L V²
+ zz + h¢arbin, + hx,toplam hksūrekli= f.5:2a
+ z1 + hpompa,f
pg
pg¥H
Wmit =
hK.yerel =Kr, hg.toplam= hx,sûrekli + hg,yerel
Nsp
%3D
Протра
(gH)3/4
一()-)(图)第-(m)(合)
1/2
wWmil
Nst =
p1/2(gH)5/4
Wmil,B _ PB (WB
(DB
DA
WB (DR
HB
WB
%3D
%3D
HA
Wmil = PgHỳNturbin
wa DA
VA
Wmil = prwv(V; – rw)(1 – cosß)
Constant operating speed characteristics; H = 55 – 460v² and ng = 8,2v – 130V3
Water is drawn from a pond by means of a centrifugal pump given with
equations, and it is pumped into a 25 m high open water reservoir with a flow
rate of 0.15 m^3/s. The pipe length used during this process is 130 m and the
continuous load coefficient on the pipe is given as 0.024. Since the local load
losses in the system are neglected; (psu= 998 kg/m³)
a) Find the diameter of the discharge pipe
b) Find the power of the pump.
c) Find the manometric head of the pump.
0,12 m
77 kW
0,10 m
83 kW
54,27 m
55,21 m
0,29 m
88 kW
O 0,20 m
O 79 kW
44,65 m
61,87 m
0,30 m
91 kW
41,54 m
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