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Considering m, = 4m,, if both masses start from %3D rest, what will be their respective velocities after m, falls for 50.0cm? Do not use dynamics and kinematics, but use an energy approach to solve this question.

Considering m, = 4m,, if both masses start from %3D rest, what will be their respective velocities after m, falls for 50.0cm? Do not use dynamics and kinematics, but use an energy approach to solve this question.

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Considering m, = 4m,, if both masses start from rest, what will be their respective velocities after m, falls for 50.0cm? Do not use dynamics and kinematics, but use an energy approach to solve m2 this question. 1 Answer: -m,gh+m,gh = m,v + 2 m,v Substitute m, = 4m, , we find that... 6g y = - 3.43- S
Transcribed Image Text:Considering m, = 4m,, if both masses start from rest, what will be their respective velocities after m, falls for 50.0cm? Do not use dynamics and kinematics, but use an energy approach to solve m2 this question. 1 Answer: -m,gh+m,gh = m,v + 2 m,v Substitute m, = 4m, , we find that... 6g y = - 3.43- S
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