Considering general shear failure , compute the gross allowable load of a rectangular footing 6m long by 1.25m wide using a load factor (FS) of 2.50. The depth of the bottom is 4.50 m below the ground surface. Cohesion of soil is 30 kPa, unit weight of soil is 19.20 kN/m3 and angle of friction is 10°.
Considering general shear failure , compute the gross allowable load of a rectangular footing 6m long by 1.25m wide using a load factor (FS) of 2.50. The depth of the bottom is 4.50 m below the ground surface. Cohesion of soil is 30 kPa, unit weight of soil is 19.20 kN/m3 and angle of friction is 10°.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
Considering general shear failure , compute the gross allowable load of a rectangular footing 6m
long by 1.25m wide using a load factor (FS) of 2.50. The depth of the bottom is 4.50 m below the
ground surface. Cohesion of soil is 30 kPa, unit weight of soil is 19.20 kN/m3 and angle of friction is
10°.
![0 Rectangular Foundation
quit = (1 + 0.301 ) c²Nc + q Na + 1 y BNY (1 - 0,20B)
L](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F88c5d538-7ca1-42eb-9f26-3d4655ed5c8f%2F738ddcd2-ae47-416f-a046-1d1cfe91e876%2F7lh8n4h_processed.png&w=3840&q=75)
Transcribed Image Text:0 Rectangular Foundation
quit = (1 + 0.301 ) c²Nc + q Na + 1 y BNY (1 - 0,20B)
L
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