Consider you have ions made from two atoms: Z has a valence electron configuration s²p4 and Q has a valence configuration of s2. What ionic formula will result from the interaction of these two ions? 1. QZ 2. Q₂Z 3. ZQ 4. ZQ₂ 5. Z₂Q 05 01 02 O 3 04

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Chapter1: Chemical Foundations
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### Question:
Consider you have ions made from two atoms: Z has a valence electron configuration \( s^2p^4 \) and Q has a valence configuration of \( s^2 \). What ionic formula will result from the interaction of these two ions?

1. QZ
2. Q\(_2\)Z
3. ZQ
4. ZQ\(_2\)
5. Z\(_2\)Q

### Options:
- ⭘ 5
- ⭘ 1
- ⭘ 2
- ⭘ 3
- ⭘ 4

### Explanation:
To deduce the correct ionic formula, we need to consider the typical ionic charges that these configurations would produce:
- Z with a valence electron configuration of \( s^2p^4 \) typically needs 2 additional electrons to achieve a stable octet structure (similar to achieving the noble gas configuration). Therefore, it would typically gain 2 electrons and form a \( Z^{2-} \) ion.
- Q with a valence configuration of \( s^2 \) typically needs to lose 2 electrons to achieve a stable configuration. Hence, it would form a \( Q^{2+} \) ion.

Combining these ions to create a neutral compound:
- \( Z^{2-} \) and \( Q^{2+} \) would combine in a 1:1 ratio to neutralize their charges.

The resulting ionic formula is **ZQ** (option 3).

### Answer:
- ⭘ 5
- ⭘ 1
- ⭘ 2
- ⭘ 3  *(selected answer)*
- ⭘ 4
Transcribed Image Text:### Question: Consider you have ions made from two atoms: Z has a valence electron configuration \( s^2p^4 \) and Q has a valence configuration of \( s^2 \). What ionic formula will result from the interaction of these two ions? 1. QZ 2. Q\(_2\)Z 3. ZQ 4. ZQ\(_2\) 5. Z\(_2\)Q ### Options: - ⭘ 5 - ⭘ 1 - ⭘ 2 - ⭘ 3 - ⭘ 4 ### Explanation: To deduce the correct ionic formula, we need to consider the typical ionic charges that these configurations would produce: - Z with a valence electron configuration of \( s^2p^4 \) typically needs 2 additional electrons to achieve a stable octet structure (similar to achieving the noble gas configuration). Therefore, it would typically gain 2 electrons and form a \( Z^{2-} \) ion. - Q with a valence configuration of \( s^2 \) typically needs to lose 2 electrons to achieve a stable configuration. Hence, it would form a \( Q^{2+} \) ion. Combining these ions to create a neutral compound: - \( Z^{2-} \) and \( Q^{2+} \) would combine in a 1:1 ratio to neutralize their charges. The resulting ionic formula is **ZQ** (option 3). ### Answer: - ⭘ 5 - ⭘ 1 - ⭘ 2 - ⭘ 3 *(selected answer)* - ⭘ 4
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