Consider using an array as a dictionary. Now assume the peculiar situation that the client may perform any number of insert operations but will only ever perform at most one lookup operation. What is the worst-case running-time of the operations performed on this data structure under the assumptions above? Briefly justify your answer.
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- Present an algorithm (in outline form) for inserting an element into a sorted linked list so that the list is always in sorted order. Do not utilize a sorting routine, but rather devise an insert (add) algorithm that will search the list and insert the new element in the proper place in the list so that the list is always in order. Assume that the objects involved all properly override both the equals (==) and the compareTo (>, <, >=, and <=) methods. The list is to be maintained in ascending order. Assume that the add method has the following signature. public void Add(E element)Given a sequence of 5 keys < 53, 66, 32, 41, 88 > for searching task: a) Given the hash function H(k) = (3.k) mod 7, insert the keys above according to its original order (from left to right) into a hash table of 7 slots. Indicate the cases of collision. Clearly show the steps and calculation with a table. b) In case of any collisions found above in a) part, determine the new slot for each collided case using Linear Probing to solve the collision problem. Clearly show your answer for each identified case. No step of calculation required. o (Answer with “NO collision found”, in case there is no collisions found above) c) In case of any collisions found above in a) part, determine the new slot ONLY for the first collided case using Double-Hashing (with functions below) to solve the collision problem. Clearly show the steps of your calculation. d1 = H(k) = (3.k) mod 7 di = (di−1 + ((5·k) mod 6) + 1) mod 7 , i ≥ 2 o (Answer with “NO collision found”, in case there is no collisions…please answer the questions clearly! Try to fill in the box with the steps of the quicksort
- Create an Ordered Doubly Linked List in C++. Remember that an ordered Linked List is one where inserts automatically place a new node so that all the nodes retain a certain order. This list should be templated where items should be in "ascending" order (i.e., if it is a list of numbers, it should be of order of least to greatest).How would you implement a dictionary of a reasonably small size n of you knew that all its elements are distinct (e.g., names of the countries in the world)? Specify an implementation of each dictionary operation.You are given a collection of N non-empty strings, denoted by S₁, S₂,..., Sn. Then you are given N-1 operations which you execute in the order they are given. The įth operation is has the following format: 'a b' (1-based indexing, without the quotes), which means that you have to make the following changes: 1. Sa = Sa+ Sb, i.e. concatenate ath string and 6th string and store the result in ath string, 2. S = "", i.e. make the 6th string empty, after doing the previous step. You are ensured that after the ith operation, there will be no future operation that will be accessing S. Given these operations to join strings, print the last string that will remain at the end of this process. Input The first line contains an integer N (1 ≤N≤ 105) denoting the number of strings given. Each of the next N lines contains a string denoting the S₁. All the characters in the string S, are lowercase alphabets from 'a' to 'z'. The total number of characters over all the strings is at most 106, i.e Σ₁|S₁|…
- Which of the following statement or statements are true ? Please check all that apply. Both the linkedlist and array size needs to be pre-decided Arrays have better cache locality that can make them better in terms of performance. It's easier to insert and delete elements from array than from the linkedlist Data type of the linked list doesnot need to be same, whereas in array, it must be the same memory can be allocated at runtime both for linkedlist and dynamic array Which of the following statements are true? Check all that applies 5 points Accessing any element of an array has the time complexity of O(n) Searching for an element in array and linkedlist has the same time complexity Inserting or Deleting an element from a stack or queue has the same time complexity Accessing an element from a singly…7. group_friends_by_food For this problem, you are given a mostly-working version of the Friend and FriendsDB classes from hw6 and hw7, and we will add new method to FriendsDB -- group_friends_by_food. group_friends_by_food returns a dictionary mapping from each of the favorite foods enjoyed by any friend to a list of the friends who enjoy that food, sorted in alphabetical order. (You can use the friends_who_love method to generate these lists.) A sample run should look like this: |>>> friend1 = Friend ("sarah", 165) >>> friend1.add_favorite_food ("strawberries") >>> friend2 - Friend ("dweezil", 175) >>> friend2.add_favorite_food("pizza") >>> friend3 = Friend("bimmy", 60) >>> friend3.add_favorite_food("pizza") >>> friend3.add_favorite_food("strawberries") >>> db = FriendsDB() >>> db.add friend (friend1) >>> db.add_friend(friend2) >>> db.add friend(friend3) >>> db.group_friends_by_food() {'strawberries': ['bimmy', 'sarah'], 'pizza': [' bimmy', 'dweezil']}Hello. Please answer the attached Hashing in Data Structures question correctly and follow all directions. Please give the solution for the problem. Do not copy the answers already given on Chegg or Bartleby. I just want your own personal answer. *If you solve the problem by yourself and it is correct I will provide a thumbs up for you. Thank you.
- The dotted-decimal notation for the IP address 10010000 10101010 01011011 00101000 The dotted-decimal notation for the IP address 10000001 10100101 01010011 00110011 2 15 19 30 41 59 77 81 85 100 Search for element 45 in the list above using a binary search algorithm. Clearly, show the first, middle, and last indexes as well as the target in every iteration. Show all the steps taken. Use the table below as a guideline with the provided format. Instructions: Start your index at 0 Show all steps Mark the first row as header(The text will be in bold). Use the index number to show the first, last, and mid Use the floor function to find the middle element If struggling to insert a table, you may work this from a Word document and upload your work using the plus sign on the editing options. First last mid 0 1 2 3 4 5 6 7 8 9 target = 45Hello. Please answer the attached Hashing in Data Structures question correctly and follow all directions. Please give the solution for the problem. Do not copy the answers already given on Chegg or Bartleby. I just want your own personal answer. *If you would like for me to give you a thumbs up then just answer the question by yourself and do not copy from outside sources. Thank you.7. group_friends_by_food For this problem, you are given a mostly-working version of the Friend and FriendsDB classes from hw6 and hw7, and we will add new method to FriendsDB -- group_friends_by_food. group_friends_by_food returns a dictionary mapping from each of the favorite foods enjoyed by any friend to a list of the friends who enjoy that food, sorted in alphabetical order. (You can use the friends_who_love method to generate these lists.) A sample run should look like this: >>> friend1 = Friend("sarah", 165) >>> friend1.add favorite_food("strawberries") >>> friend2 Friend("dweezil", 175) >>> friend2.add_favorite_food("pizza") >>> friend3 Friend("bimmy", 60) >>> friend3.add_favorite_food("pizza") >>> friend3.add favorite_food ("strawberries") >>> db FriendsDB() %3D >>> db.add_ friend(friend1) >>> db.add_friend(friend2) >>> b.add_friend (friend3) >>> db.group_friends_by_food() {'strawberries': ['bimmy', 'sarah'], 'pizza': ['bimmy', 'dweezil']}