Consider two samples of ethane: C¿H6 (g) and ethane-d6: C2D6 (g) at -30 °C and 2.0 atm. Deuterium (D) is an isotope of hydrogen with atomic mass = 2.014 amu. Calculate the urms and the fraction of molecules that have speed equal to urms for each of the two ethane samples. With reference to the Boltzmann-Maxwell curve, explain the differences in both ums and the fractions of molecules obtained. Given that 3RT and M 3/2 Mu² F(u) = 47| \2TRT Urms u?e-(ZRT %3D M Predict the ratio of 'rate of effusion of C2H6' to that of C2D6. Show your calculations and reasoning.
Consider two samples of ethane: C¿H6 (g) and ethane-d6: C2D6 (g) at -30 °C and 2.0 atm. Deuterium (D) is an isotope of hydrogen with atomic mass = 2.014 amu. Calculate the urms and the fraction of molecules that have speed equal to urms for each of the two ethane samples. With reference to the Boltzmann-Maxwell curve, explain the differences in both ums and the fractions of molecules obtained. Given that 3RT and M 3/2 Mu² F(u) = 47| \2TRT Urms u?e-(ZRT %3D M Predict the ratio of 'rate of effusion of C2H6' to that of C2D6. Show your calculations and reasoning.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Consider two samples of ethane: C2H6 (g) and ethane-d6: C2D6 (g) at –30 °C and 2.0 atm.
Deuterium (D) is an isotope of hydrogen with atomic mass = 2.014 amu.
Calculate the Urms and the fraction of molecules that have speed equal to Urms for each of the
two ethane samples. With reference to the Boltzmann-Maxwell curve, explain the differences
in both ums and the fractions of molecules obtained.
3RT
3/2
u?e-2RT
Ми?
Given that
and
M
F(u) = 47
Urms
M
2TRT.
Predict the ratio of 'rate of effusion of C2H6’ to that of C2D6. Show your calculations and
reasoning.
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