Consider two negative charges, -/q/ and -/3q/, held fixed at the base of an equilateral triangel of side length s. The remaining vertex of the triangle is point P. Let q = -1.00 nC, and s = 3.00 cm. (A.) What is the potential energy of this system of two charges? U = 9e-7 (B.) What is the electric potential at point P? Vp = -1200 (C.) How much work will it take (similarly, what will be the change in the electric potential energy of the system) to bring a third negative charge (-/q/) to point P from a very large distance away? W = AU = 4e-6 (D.) If the third charged particle (-/g/) is placed at point P, but not held fixed, it will experience a repellent force and accelerate away from the other two charges. If the mass of the third particle is m 5.00 x 10-12 kg, what will the speed of this charged particle be once it has moved a very large distance away? m/s

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Consider two negative charges, -/g/ and -/3q/, held fixed at the base of an equilateral triangel of side length s. The remaining vertex of the triangle is point P.
Let q = -1.00 nC, and s = 3.00 cm.
(A.) What is the potential energy of this system of two charges?
U = 9e-7
(B.) What is the electric potential at point P?
Vp = |-1200
V
(C.) How much work will it take (similarly, what will be the change in the electric potential energy of the system) to bring a third negative charge (-/q/) to point P from a very large distance away?
W = AU = 4e-6
X J
(D.) If the third charged particle (-/g/) is placed at point P, but not held fixed, it will experience a repellent force and accelerate away from the other two charges. If the mass of the third particle is m =
5.00 x 10-12 kg, what will the speed of this charged particle be once it has moved a very large distance away?
V =
m/s
Transcribed Image Text:Consider two negative charges, -/g/ and -/3q/, held fixed at the base of an equilateral triangel of side length s. The remaining vertex of the triangle is point P. Let q = -1.00 nC, and s = 3.00 cm. (A.) What is the potential energy of this system of two charges? U = 9e-7 (B.) What is the electric potential at point P? Vp = |-1200 V (C.) How much work will it take (similarly, what will be the change in the electric potential energy of the system) to bring a third negative charge (-/q/) to point P from a very large distance away? W = AU = 4e-6 X J (D.) If the third charged particle (-/g/) is placed at point P, but not held fixed, it will experience a repellent force and accelerate away from the other two charges. If the mass of the third particle is m = 5.00 x 10-12 kg, what will the speed of this charged particle be once it has moved a very large distance away? V = m/s
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