Consider two independent random samples with the following results: n₁ = 562 n₂ = 356 Use this data to find the 98 % confidence interval for the true difference between the population proportions. x₁ = 321 X₂ = 87 Step 2 of 3: Find the margin of error. Round your answer to six decimal places.

Q: A 93.32% Cl is given as (2.5, 3.5). From this information, find a 95% confidence interval (yes, this…

A: The provided information is as follows:The 93.32% confidence interval is (2.5,3.5).

Q: Choose the appropriate statistical test. When computing, be sure to round each answer as indicated.…

A: Introduction:  According to the nature of t-distribution when the sample size gets larger and larger…

Q: Find the value of the sample size needed if the confidence interval is 95% that the sample…

A: Given that  Margin of error =E =0.04 Sample proportion p^=0.45

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A: We find Margin of Error (M.E)  for 95% C.I. (d) (e)

Q: A sample of 25 bottles of orange juice were measured and the sample standard deviation is 1.8…

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Q: Use the confidence interval to find the margin of error and the sample mean. (0.498,0.640) The…

A: Confidence interval is 0.498, 0.640 To find :  (i) margin of error (ii) sample mean Margin of error…

Q: You sample 36 families to find out how much they spent on groceries last month. Your sample mean is…

A: Given data,n=36x=540s=82α=0.05

Q: d. FIND t a n = 10 for the 90% confidence interval for the mean. %3D

A: d. Given: n=10 α=0.1 The degrees of freedom is obtained as below: df=n-1=10-1=9 Critical value: The…

Q: Use the confidence interval to find the margin of error and the sample mean. (0.228,0.390) The…

A: Given, C.I is (0.228,0.390) Margin of error(E)=?

Q: If n = 108, a = 29 and o = 2.6, construct a 91% confidence interval. Give your answers to three…

A: Since we know population standard deviation, use z-distribution to find z-critical value.…

Q: If n = 220,p = 0.4,then what will be the 87.4% confidence interval for the population proportion?

A:

Q: n Find the size of the sample needed to estimate the difference between the proportions of Democrats…

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Q: Find a 95% confidence interval for a mean, µ, where n = 324, x̄ = 2.7, s = .91, and se = .06.

A: Given: n = 324, x̄ = 2.7, s = .91, se = .06.

Q: 61 students are asked in a survey how many hours they work during a week. Their responses have a…

A: The random variable X follows normal distribution. The sample size is 61. The sample mean is 24. The…

Q: find the margin of error for a sample mean, given n=16, s=4, Xbar=17. for a 95% confidence interval.

A: The margin of error for sample mean is given by,

Q: Find the margin of error for the 95% confidence interval used to estimate the population proportion.…

A: Confidence level = 95% Sample size (n) = 2440 Sample proportion (p̂) = 0.70

Q: Given two independent random samples with the following results: n₁ = 99 n₂ = 337 x₁ = 27 x₂ = 245…

A: Givenn1=99      n2=337x1=27      x2=245confidence level=99%

Q: na survey, the planning value for the population proportion is p* = 0.25. How large a sample should…

A:

Q: For a confidence level of 80% with a sample size of 24, find the t-score.

A: From the provided information, Confidence level = 80% Level of significance (α) = 1 – 0.80 = 0.20…

Q: you want to obtain a sample to estimate a population mean. based on previous evidence, you believe…

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Q: Step 2 of 3: Find the margin of error to be used in constructing the confidence interval. Round your…

A: Given: n1=13x¯1=180s1=20n2=6x¯2=197s2=11

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: Margin of error (E) for proportion is defined as below                                E = Width2…

Q: Assume that population mean is to be estimated from the sample described. Use the sample results to…

A: Given95% confidence interval N=361 x = 59.1 seconds. z= 4.9 SecondsFind the margin of error?

Q: Remember the formula for the 80% confidence interval of a single proportion(see picture) : what is…

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Q: The estimated prevalence is 11%, and the desired confidence level is 91% with a margin of error of…

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Q: Use the confidence interval to find the margin of error and the sample mean. (0.278,0.400) The…

A: We have given the confidence interval(0.278, 0.400)Lower limit = 0.278Upper limit = 0.400

Q: You sample 40 dogs and find a sample mean weight of 60 lbs with a sample standard deviation of 5.…

A: From the provided information, Sample size (n) = 40 Sample mean (x̅) = 60 lbs Sample standard…

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A: Student advisors are interested in determining if the variances of scores of day students and night…

Q: Consider two independent random samples with the following results: n1=568pˆ1=0.44   n2=624pˆ2=0.33…

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Q: The number of successes and the sample size are given for a simple random sample from a population.…

A: Obtain the value of sample proportion. The value of sample proportion is obtained below: From the…

Q: A survey of folk music fans yield this 95% confidence interval estimate of the proportion of fans…

A: Introduction:The 95% confidence interval for the requires proportion is (0.74, 0.86). So, lower…

Q: You are given the sample mean and the population standard deviation. Use this information to…

A: n=47, sample mean =111.62, standard deviations=11.42

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Q: Q15 The systolic blood pressures (in mmHg) of a random sample of adults have been recorded. A 95%…

A: Given that  95% confidence interval is (100, 125) Margin of error =E  Sample mean =X̄

Q: FIND t a n = 15 for the 98% confidence interval for the mean.

A: Provided information that, n=15 Alpha (α)=1-0.98=0.02 α/2=0.01

Q: A population of N = 6 scores has ΣX = 42. What is the population mean?

A: Given ,Population of N=6 scoresand Σx =42

Q: Solve this for me

A: Given:sample size n=35sample mean x̄=1.41sample standard deviation s=1.19population standard…

Q: f n=200 and X=80​, construct a 99​% confidence interval estimate for the population proportion.

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Q: Use the confidence interval to find the margin of error and the sample mean. (0.264,0.420) ......…

A: Given confidence interval is(0.264  ,  0.420)

Q: If X= 102, o=9, and n=63, construct a 95% confidence interval estimate of the population mean, μ.

A: Formula to constructing the confidence interval about mean , when the population standard deviation…

Q: If Xbar=93​, σ=13​, and n=62​, construct a 99​% confidence interval estimate of the population​…

A: Given that  Sample size: n=62 Sample mean: x¯=93 Population standard deviation: σ=13 Confidence…

Q: If X=72​, σ=13​, and n=66​, construct a 95​% confidence interval estimate of the population​…

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Q: Assume that a sample is used to estimate a population proportion p. Find the margin of error E that…

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Q: Use the confidence interval to find the margin of error and the sample mean. (12, 20) O E = 4, X =…

A: confidence interval for mean : (12,20)

Q: Use a t-distribution to find a confidence interval for the difference in means μ = μ₁-₂ using the…

A: From the provided information, Sample size (n) = 8

Q: Suppose a sample of 779 tenth graders is drawn. Of the students sampled, 202 read at or below the…

A: In question, Given that a sample of 779 tenth graders is drawn. Of the students sampled, 202 read at…