Consider two independent populations that are normally distributions. A simple random sample of n1=41n1=41 from the first population showed x¯1=33, and a simple random of size n2=48 from the second population showed x¯2=32.Suppose s1=9 and s2=10, find a 98% confidence interval for μ1-μ2. (Round answers to two decimal places.)margin of error: lower limit: upper limit:
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Consider two independent populations that are
Suppose s1=9 and s2=10, find a 98% confidence interval for μ1-μ2. (Round answers to two decimal places.)
margin of error:
lower limit:
upper limit:
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- In random, independent samples of 225 adults and 200 teenagers who watched a certain television show, 112 adults and 138 teens indicated that they liked the show. Let p1 be the proportion of all adults watching the show who liked it, and let p2 be the proportion of all teens watching the show who liked it. Find a 95% confidence interval for −p1p2. Then find the lower limit and upper limit of the 95% confidence interval. Carry your intermediate computations to at least three decimal places. Round your responses to at least three decimal places. a.) The Lower Limit is: b.) The Upper Limit is:Consider two independent populations that are normally distributions. A simple random sample of n1=41 from the first population showed x¯1=33, and a simple random of size n2=48n from the second population showed ¯x2=32Suppose s1=9 and s2=10, find a 98% confidence interval for μ1-μ2. (Round answers to two decimal places.)margin of error: lower limit: upper limit:A consumer group claims that the mean minimum time it takes for a sedan to travel a quarter mile is greater than 14.5 seconds. A random sample of 24 sedans has a mean minimum time to travel a quarter mile of 15.4 seconds and a standard deviation of 2.09 seconds. At α=0.01 is there enough evidence to support the consumer group's claim? Complete parts (a) through (d) below. Assume the population is normally distributed.
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Find the mean and the standard deviation of X of B(144, 0.49). Round off to 4 decimal places. O = b. Now approximate X of B(144, 0.49) using the normal approximation with the random variable Y and the table. Round off to 4 decimal places. Y - N( c. Find the probability that at most 81 favor a charter school using the normal approximation and the table. (Round off to z-values up to 2 decimal places.) P(X 75) - P(Y > a (Z > e. Find the probability that exactly 81 favor a charter school using the normal approximation and the table. (Round off to z-values up to 2 decimal places.) P(X = 81) - P(A sample of n=25 scores has a mean of M=68. Find the z-score for this sample: If it was obtained from a population with m=60 and s=10. If it was obtained from a population with m=60 and s=20. If it was obtained from a population with m=60 and s=40. A normal distribution has a mean of μ = 54 and a standard deviation of σ = 6. What is the probability of randomly selecting a score less than X = 51? What is the probability of selecting a sample of n = 4 scores with a mean less than M = 51? What is the probability of selecting a sample of n = 36 scores with a mean less than M = 51? A sample is selected from a population with a mean of and a standard deviation of . If the sample has scores, what is the expected value of and the standard error of If the sample has scores, what is the expected value of and the standard error of ? A random sample is obtained from a normal population with a mean of and a standard deviation of . The sample mean is Is this a…Independent samples of size n1 = 25 and n2 = 36 are taken from two normal populations with knownstandard deviations of σ1 = 5.5 and σ2 = 4.2. e sample means are x¯1 = 13.6 and x¯2 = 19.2. Find a95% confidence interval for µ1 − µ2.A simple random sample of size n=40 is drawn from a population. The sample mean is found to be 107.6, and the sample standard deviation is found to be 20.2. Is the population mean greater than 100 at the α=0.025 level of significance? Determine the null and alternative hypotheses. H0: mu equals 100μ=100 mu less than 100μ<100 mu equals 100μ=100 mu greater than 100μ>100 mu less than 107.6μ<107.6 mu equals 107.6μ=107.6 mu greater than 107.6μ>107.6 H1: mu greater than 100μ>100 mu less than 100μ<100 mu equals 100μ=100 mu greater than 100μ>100 mu less than 107.6μ<107.6 mu equals 107.6μ=107.6 mu greater than 107.6μ>107.6 Compute the test statistic. t 0t0 t 0t0 z 0z0 = (Round to two decimal places as needed.) Determine the P-value. The P-value is . (Round to three decimal places as needed.) What is the result of the hypothesis test? the null hypothesis because the P-value is the level of significance.…A sample of n = 7 scores is selected from a population with an unknown mean ( µ). The sample has a mean of M = 40 and a variance of s 2 = 63. 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