Consider two continuous random variables X and Y, where Y~U(1,3) and X|Y = y - U(0,1/y). (a) State E(X|Y = y) and hence, using the method of iterated expectations, find E(X) (b) Show that the joint probability density function of X and Y is fxx (x, y) = {'/2. P/2, 0

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A: Check the solution in the explanation.Explanation:Check the image below for a detailed solution.

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A: It is an important part of statistics. It is widely used.

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A: Hello! As you have posted more than 3 sub parts, we are answering the first 3 sub-parts.  In case…

Q: 6) X is a continuous random variable with the following probability density function: fx(x) = 2x,…

A: probability density function of Y=1-X : =&gt;   fY(y) = 2-2y ,     0&lt;y&lt;1Explanation:

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Q: 5. (12') Let X be a random variable with the probability density function Jax+b, S(x) = { 0,…

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A: Hello! As you have posted more than 3 sub parts, we are answering the first 3 sub-parts.  In case…

Q: (4) If X is a continuous random variable with p. d. f. (X) 1 f(x) = }6 ,0<x< 3 12 ,othewise The…

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Q: (b) Suppose X1, X2, ...,Xn are iid Random variables with density function 1 f(x) = -еxp 20 p(-),…

A: (b)

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A: Given:- f(x, y)=x y2+x28,0≤x≤2,0≤x≤1

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A: The probability density function for the two variables are : fξ(x)=4e-4x ,x&gt;0fη(y)=6e-6y ,y&gt;0…

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A: X and Y denote  jointly continuous rvs.The joint density function:

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A: Let x be a uniform random variable in the interval (0, 1).

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A: Joint probability mass function of X and Y is given as: PX=xi,Y=yi=xi2 yi30,    xi=1,2 ; yi=1,2,3