Consider three point charges at the corners of a triangle, as shown in the figure, where q, = 5.50 x 10 C, q, = -1.60 x 10-° C, and q3 = 5.50 x 10-° C. Suppose a fourth charge, 94 = -9,, is placed so that the net force on q, is zero. Whatis the distance (in m) between q, and 94?F9336.9° F1s sin (36.994.00 m92F13 cos (36.9°)933.00 m5.00 m91

Given, q1 = 5.50 × 10-9 C q2 = -1.60 × 10-9 Cq3 = 5.50 × 10-9 C

Consider three point charges at the corners of a triangle, as shown in the figure, where q, = 5.50 x 10-9 C, q2 = -1.60 x 10- C, and q, = 5.50 x 10- C. Suppose a fourth charge, q4 = -9,, is placed so that the net force on q, is zero. What iş the distance (in m) between q, and q.? 36,9° Fis sin (36.99 Fis cos (36.9 4.00 m 99 3.00 m 5.00 m 91

Consider three point charges at the corners of a triangle, as shown in the figure, where q, = 5.50 x 10-9 C, q2 = -1.60 x 10- C, and q, = 5.50 x 10- C. Suppose a fourth charge, q4 = -9,, is placed so that the net force on q, is zero. What iş the distance (in m) between q, and q.? 36,9° Fis sin (36.99 Fis cos (36.9 4.00 m 99 3.00 m 5.00 m 91