Consider this IP address 153.182.201.187 with a broadcast address (of this subnet) given by 153.182.201.191 Choose all the possible masks that could have been used

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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Consider this IP address 153.182.201.187 with a broadcast address (of this subnet) given by
153.182.201.191
Choose all the possible masks that could have been used
255.255.255.224
255.255.254.0
255.255.255.248
255.255.255.240
255.255.255.0
255.255.255.252
255.255.255.128
187 is 10111011 and 191 is 10111111 so can not be 128 or 192
255.255.255.224
255.255.255.248
255.255.255.240
Transcribed Image Text:Consider this IP address 153.182.201.187 with a broadcast address (of this subnet) given by 153.182.201.191 Choose all the possible masks that could have been used 255.255.255.224 255.255.254.0 255.255.255.248 255.255.255.240 255.255.255.0 255.255.255.252 255.255.255.128 187 is 10111011 and 191 is 10111111 so can not be 128 or 192 255.255.255.224 255.255.255.248 255.255.255.240
Consider this IP address 53.182.201.17 with this mask 255.255.224.0
Choose all the following valid IP Host addresses within the same subnet
53.182.192.0
53.182.222.17
53.182.223.255
53.182.0.17
53.182.192.255
53.182.201.255
53.182.23.54
53.182.243.24
Transcribed Image Text:Consider this IP address 53.182.201.17 with this mask 255.255.224.0 Choose all the following valid IP Host addresses within the same subnet 53.182.192.0 53.182.222.17 53.182.223.255 53.182.0.17 53.182.192.255 53.182.201.255 53.182.23.54 53.182.243.24
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