Consider this algorithm: // PRE: A an array of numbers, initially low = 0, high = size of A - 1 // POST: Returns the position of the pivot, and A is partitioned with elements to the left of the pivot being <= pivot, // // and elements to the right of the pivot being >=pivot int partition (A, low, high): 1. 2. pivot =A[high] i = low-1 for j from low to (high-1) do: if pivot >A[j] then do: i = i + 1 swap A[j] with A[i] swap A[i+1] with the pivot element at A [high] return (i+1) Prove correctenss of partition. Use partition to write a version of Quicksort that sorts a numerical array A in place.
Consider this algorithm: // PRE: A an array of numbers, initially low = 0, high = size of A - 1 // POST: Returns the position of the pivot, and A is partitioned with elements to the left of the pivot being <= pivot, // // and elements to the right of the pivot being >=pivot int partition (A, low, high): 1. 2. pivot =A[high] i = low-1 for j from low to (high-1) do: if pivot >A[j] then do: i = i + 1 swap A[j] with A[i] swap A[i+1] with the pivot element at A [high] return (i+1) Prove correctenss of partition. Use partition to write a version of Quicksort that sorts a numerical array A in place.
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![Consider this algorithm:
// PRE: A an array of numbers, initially low
=
0, high
= size of A - 1
// POST: Returns the position of the pivot, and A is partitioned with
elements to the left of the pivot being <= pivot,
//
//
and elements to the right of the pivot being >=pivot
int partition (A, low, high):
1.
2.
pivot =A[high]
i = low-1
for j from low to (high-1) do:
if pivot >A[j] then do:
i = i + 1
swap A[j] with A[i]
swap A[i+1] with the pivot element at A [high]
return (i+1)
Prove correctenss of partition.
Use partition to write a version of Quicksort that sorts a
numerical array A in place.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F602caea4-3d4d-49a2-a5cf-03841bb038cc%2F55a64d17-0073-40b3-94e7-d83b8b440350%2Fxsu4c37_processed.png&w=3840&q=75)
Transcribed Image Text:Consider this algorithm:
// PRE: A an array of numbers, initially low
=
0, high
= size of A - 1
// POST: Returns the position of the pivot, and A is partitioned with
elements to the left of the pivot being <= pivot,
//
//
and elements to the right of the pivot being >=pivot
int partition (A, low, high):
1.
2.
pivot =A[high]
i = low-1
for j from low to (high-1) do:
if pivot >A[j] then do:
i = i + 1
swap A[j] with A[i]
swap A[i+1] with the pivot element at A [high]
return (i+1)
Prove correctenss of partition.
Use partition to write a version of Quicksort that sorts a
numerical array A in place.
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