Medical practitioners are increasingly utilising the Zoom platform. Not only for online meetings but also for consultations with patients. The weekly Zoom access time (in hours) at two hospitals:Health Care I Health Care II needs to be investigated.Given: The weekly access time of medical practitioners at both hospitals is normally distributed with a standard deviation of σ=5σ=5 hours. Both Questions are under on question, please answer in full. Thank you your assistance is greatly appreciated b)Consider the weekly access time at Health Care IIThe Superintendent wants to investigate the average weekly access time (in hours) at Health Care II based on 2 different research questions. A randomsample of the weekly access times of n = 30 medical practitioners revealed an average of = 27.05 hours.Let: u = mean weekly access time of the medical practitioners.Research Question 1: Is the mean weekly access time less than 28 hours?Given: The value of the test statistic isz = -1.04Complete the following:Identify the correct null hypothesis:О Но : д < 28О Но : х — 28О Но : и < 27.05О Но : и 28O Ho : ã + 27.05O Ho : µ = 28О Но : а < 27.05o Ho :ã # 28О Но: а <28О Но : и — 27.05О Но : а — 27.05О Но : а > 28O Ho : µ + 27.05О Но : и > 27.05О Но : и > 28O Ho : ã > 27.05The p-value is:Round your answer to 4 decimal places. a)Consider the weekly access time at Health Care IGiven:X = the weekly access time of a medical practitioner.The mean weekly access time is u = 20 hours.Complete the following: (Round your answers to 4 decimal places.)The probability that the weekly access time of a randomly selected medical practitioner is between 16 and 25 hours is:Only 20% of the medical practitioners had a weekly access time ofhours or more.Given:= the average weekly access time of a random sample of n = 30 medical practitioners.The standard error of X is oI= 0.9129.Complete the following: (Round your answers to 4 decimal places.)Ninety-five percent of the average weekly access times are withinhours of the mean u = 20.The probability that X is at least 20.8 hours is:

Answered: Consider the weekly access time at…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

Medical practitioners are increasingly utilising the Zoom platform. Not only for online meetings but also for consultations with patients. The weekly Zoom access time (in hours) at two hospitals:

Health Care I
Health Care II

needs to be investigated.

Given: The weekly access time of medical practitioners at both hospitals is normally distributed with a standard deviation of σ=5σ=5 hours.

Both Questions are under on question, please answer in full. Thank you your assistance is greatly appreciated

b)
Consider the weekly access time at Health Care II
The Superintendent wants to investigate the average weekly access time (in hours) at Health Care II based on 2 different research questions. A random
sample of the weekly access times of n = 30 medical practitioners revealed an average of = 27.05 hours.
Let: u = mean weekly access time of the medical practitioners.
Research Question 1: Is the mean weekly access time less than 28 hours?
Given: The value of the test statistic is
z = -1.04
Complete the following:
Identify the correct null hypothesis:
О Но : д < 28
О Но : х — 28
О Но : и < 27.05
О Но : и 28
O Ho : ã + 27.05
O Ho : µ = 28
О Но : а < 27.05
o Ho :ã # 28
О Но: а <28
О Но : и — 27.05
О Но : а — 27.05
О Но : а > 28
O Ho : µ + 27.05
О Но : и > 27.05
О Но : и > 28
O Ho : ã > 27.05
The p-value is:
Round your answer to 4 decimal places.

a)
Consider the weekly access time at Health Care I
Given:
X = the weekly access time of a medical practitioner.
The mean weekly access time is u = 20 hours.
Complete the following: (Round your answers to 4 decimal places.)
The probability that the weekly access time of a randomly selected medical practitioner is between 16 and 25 hours is:
Only 20% of the medical practitioners had a weekly access time of
hours or more.
Given:
= the average weekly access time of a random sample of n = 30 medical practitioners.
The standard error of X is oI
= 0.9129.
Complete the following: (Round your answers to 4 decimal places.)
Ninety-five percent of the average weekly access times are within
hours of the mean u = 20.
The probability that X is at least 20.8 hours is:

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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