Consider the vectors 7₁ = €₂ = T3 = 1 in R4. Use the Gram-Schmidt process to find an orthogonal basis for the subspace span{1, 72, 73}.
Consider the vectors 7₁ = €₂ = T3 = 1 in R4. Use the Gram-Schmidt process to find an orthogonal basis for the subspace span{1, 72, 73}.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Note first that the vectors 71, 72, and 73 are linearly independent (a necessary precondition for performing
the Gram-Schmidt process); you can check this by row-reducing the coefficient matrix [₁
confirming that all three columns have pivots. Gram-Schmidt then produces the orthogonal basis
2 3] and
1/2
-2/3
{V1, U2, U3} =
2/3
181
2/3
0
If you like, you can scale the second and third vectors to clear fractions (the result will still be an orthogonal
basis).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffa923b6f-81dd-482c-8885-6de6bc295751%2F4aa247df-58b6-43ee-a283-e2548a4908d3%2F4shf2um_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Answer
Note first that the vectors 71, 72, and 73 are linearly independent (a necessary precondition for performing
the Gram-Schmidt process); you can check this by row-reducing the coefficient matrix [₁
confirming that all three columns have pivots. Gram-Schmidt then produces the orthogonal basis
2 3] and
1/2
-2/3
{V1, U2, U3} =
2/3
181
2/3
0
If you like, you can scale the second and third vectors to clear fractions (the result will still be an orthogonal
basis).

Transcribed Image Text:Consider the vectors
€₁ =
₂ =
3: = 1
in R4. Use the Gram-Schmidt process to find an orthogonal basis for the subspace span{1, 72, 73}.
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