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Consider the unsteady mass conservation equation (1.5) as it might describe the flow accelerating through a duct with a variable cross section. If the largest velocity gradient measured locally is du/dx and the largest density gradient is dpldx, what order-of-magnitude relationship must exist between du/dx and dpldx for the simplified equation (1.8) to be applicable? Q: ap + u aw + = 0 az ay ap Hint 1: ap ay + v- + w (1.5) ax ax du dv aw Hint 2: ax (1.8) dy az + +

Consider the unsteady mass conservation equation (1.5) as it might describe the flow accelerating through a duct with a variable cross section. If the largest velocity gradient measured locally is du/dx and the largest density gradient is dpldx, what order-of-magnitude relationship must exist between du/dx and dpldx for the simplified equation (1.8) to be applicable? Q: ap + u aw + = 0 az ay ap Hint 1: ap ay + v- + w (1.5) ax ax du dv aw Hint 2: ax (1.8) dy az + +

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Q: Consider the unsteady mass conservation equation (1.5) as it might describe the flow accelerating through a duct with a variable cross section. If the largest velocity gradient measured locally is du/dx and the largest density gradient is dpldx, what order-of-magnitude relationship must exist between du/dx and dpldx for the simplified equation (1.8) to be applicable? ap ap +p ax ap ap du av Hint 1: aw + = 0 az +u at ax (1.5) + v. +w. ду az ду du aw Hint 2: ax (1.8) ду
Transcribed Image Text:Q: Consider the unsteady mass conservation equation (1.5) as it might describe the flow accelerating through a duct with a variable cross section. If the largest velocity gradient measured locally is du/dx and the largest density gradient is dpldx, what order-of-magnitude relationship must exist between du/dx and dpldx for the simplified equation (1.8) to be applicable? ap ap +p ax ap ap du av Hint 1: aw + = 0 az +u at ax (1.5) + v. +w. ду az ду du aw Hint 2: ax (1.8) ду
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