### Experiment DescriptionConsider the two trials shown below and provide structures for the products formed:#### Trial 1- **Reactants**: A benzaldehyde structure with NaBH₄ (Sodium Borohydride) in CH₃OH (Methanol).- **Results**: One product is formed with a reaction time of 1 minute.#### Trial 2- **Reactants**: A cyclohexanone structure with NaBH₄ in CH₃OH.- **Results**: One product is formed with a reaction time of 30 seconds.#### Trial 3- **Reactants**: A benzophenone structure with NaBH₄ in CH₃OH.- **Results**: No reaction after 5 minutes.### Questions for Analysis**A. Explain why trial 2 took less time than trial 1 to form product.****B. Explain why trial 3 did not form any product.**### Explanation of DiagramsThe diagrams depict chemical reactions using structural formulas for organic compounds. Each trial involves the use of Sodium Borohydride (NaBH₄) as a reducing agent in Methanol (CH₃OH) as the solvent. The results column indicates whether a product was formed and the time taken or if no reaction occurred.

NaBH4 is a good reducing agent and can reduce aldehyde and ketone .1.Trial 2.Trial3.Trial 3 ( It is the possible product only).A.Trial 2 will less time as it is more reactive than 1 because reactivity of aldehyde is more than than ketone.B.Trial 3 will not form product as it is already present in stable form.A.Trial 2 will less time as it is more reactive than 1 because reactivity of aldehyde is greater than than ketone.B.Trial 3 will not form product as it is already present in stable form.