can you anser this question using figure 1? thank you. Consider the truss made of 2 bars with lengths 1 m, orientated in the structure shown in Figure 1. Thetwo bars have the same cross-sectional areas A = 5·10−4 m² and modulus of elasticity E = 210¹¹ N/m².A force of F1.x = 10 kN is applied in the x-direction at node 1.450290°211m31mF1,x = 10KNXFigure 1: Truss assembly formed of two bars. Nodes and bars are numbered, with bars numberedwith underlines. Apply the boundary conditions and specified forces to your global stiffness system of equationsand solve for the displacements.

Answered: Image /qna-images/answer/f01b20b8-f3b2-4e33-9de7-b5127dcf57c6.jpg

Consider the truss made of 2 bars with lengths 1 m, orientated in the structure shown in Figure 1. The two bars have the same cross-sectional areas A = 5.10-4 m² and modulus of elasticity E = 2.10¹¹ N/m². A force of F₁,x= 10 kN is applied in the x-direction at node 1.

Consider the truss made of 2 bars with lengths 1 m, orientated in the structure shown in Figure 1. The two bars have the same cross-sectional areas A = 5.10-4 m² and modulus of elasticity E = 2.10¹¹ N/m². A force of F₁,x= 10 kN is applied in the x-direction at node 1.

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter2: Axially Loaded Members

Section: Chapter Questions

Problem 2.11.4P: A prismatic bar in tension has a length L = 2.0 m and cross-sectional area A =249 mn2. The material...

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Concept explainers

Strain energy

The term strain indicates the variation in an object's length, area, and volume when the object is subjected to an external force. The external force may be of normal, shear, moment, torque, etc. The strain in an object depends on the types of external force and cross-section of the object. Mathematically, the evaluation of strain can be obtained with the help of elastic constants.

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can you anser this question using figure 1? thank you.

Consider the truss made of 2 bars with lengths 1 m, orientated in the structure shown in Figure 1. The
two bars have the same cross-sectional areas A = 5·10−4 m² and modulus of elasticity E = 210¹¹ N/m².
A force of F1.x = 10 kN is applied in the x-direction at node 1.
450
2
90°
2
1
1m
3
1m
F1,x = 10KN
X
Figure 1: Truss assembly formed of two bars. Nodes and bars are numbered, with bars numbered
with underlines.

Apply the boundary conditions and specified forces to your global stiffness system of equations
and solve for the displacements.

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Consider the truss made of 2 bars with lengths 1 m, orientated in the structure shown in Figure 1. The two bars have the same cross-sectional areas A = 5-104 m² and modulus of elasticity E= 210¹¹ N/m². A force of F1,x = 10 kN is applied in the x-direction at node 1. 900 45° 2 = AE L IN 2 1 1m 3 1m → F₁x = 10KN Figure 1: Truss assembly formed of two bars. Nodes and bars are numbered, with bars numbered with underlines. y a) Using the numbering system of nodes and bars shown in Figure 1, state the 2 local stiffness matrices for each bar and combine these into a global stiffness system for all nodal displacements of the truss. Use the matrix system given in Eq. 1 below relating the local displacements of a single bar to the local forces applied to its nodes. fix fiy fjr fjv. Here C = cos(0) and S = sin(0), where is the angle of orientation of the bar. U₂ CS -C²-CS S² -CS -S² Vi CS -C² -CS C² CS Uj -CS -S² CS S² (1) b) Apply the boundary conditions and specified forces to your global…
Consider the truss made of 2 bars with lengths 1 m, orientated in the structure shown in Figure 1. The two bars have the same cross-sectional areas A = 5-10-4 m² and modulus of elasticity E = 2.10¹¹ N/m². A force of F1.x = 10 kN is applied in the x-direction at node 1. 450 2 90⁰ 2 1 1m C² AE CS L 3 1m → F₁x = 10KN Figure 1: Truss assembly formed of two bars. Nodes and bars are numbered, with bars numbered with underlines. a) Using the numbering system of nodes and bars shown in Figure 1, state the 2 local stiffness matrices for each bar and combine these into a global stiffness system for all nodal displacements of the truss. Use the matrix system given in Eq. 1 below relating the local displacements of a single bar to the local forces applied to its nodes. fix fiy fjx fjy Here C = cos(0) and S = sin(0), where is the angle of orientation of the bar. 38 -S² Vi CS U j S² CS -C² -CS C2 S² -C² -CS -CS -S² CS (1)
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