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Consider the truss made of 2 bars with lengths 1 m, orientated in the structure shown in Figure 1. The two bars have the same cross-sectional areas A = 5.10-4 m² and modulus of elasticity E = 2·10¹¹ N/m². 10 kN is applied in the x-direction at node 1. A force of F1,x = 900 450 2 1 2 1 1m 3 1m → F₁x = 10KN y Figure 1: Truss assembly formed of two bars. Nodes and bars are numbered, with bars numbered with underlines.

Consider the truss made of 2 bars with lengths 1 m, orientated in the structure shown in Figure 1. The two bars have the same cross-sectional areas A = 5.10-4 m² and modulus of elasticity E = 2·10¹¹ N/m². 10 kN is applied in the x-direction at node 1. A force of F1,x = 900 450 2 1 2 1 1m 3 1m → F₁x = 10KN y Figure 1: Truss assembly formed of two bars. Nodes and bars are numbered, with bars numbered with underlines.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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can you help me answer this question using figure 1. thank you.

Consider the truss made of 2 bars with lengths 1 m, orientated in the structure shown in Figure 1. The two bars have the same cross-sectional areas A = 5·10−4 m² and modulus of elasticity E = 210¹¹ N/m². A force of F1.x = 10 kN is applied in the x-direction at node 1. 450 2 90° 2 1 1m 3 1m F1,x = 10KN X Figure 1: Truss assembly formed of two bars. Nodes and bars are numbered, with bars numbered with underlines.
Transcribed Image Text:Consider the truss made of 2 bars with lengths 1 m, orientated in the structure shown in Figure 1. The two bars have the same cross-sectional areas A = 5·10−4 m² and modulus of elasticity E = 210¹¹ N/m². A force of F1.x = 10 kN is applied in the x-direction at node 1. 450 2 90° 2 1 1m 3 1m F1,x = 10KN X Figure 1: Truss assembly formed of two bars. Nodes and bars are numbered, with bars numbered with underlines.
What is the force required on node 1 for the displacement of the node 1 to be u₁ = 1.10-4 m and V₁ = 0 m. V1
Transcribed Image Text:What is the force required on node 1 for the displacement of the node 1 to be u₁ = 1.10-4 m and V₁ = 0 m. V1
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