Consider the transformer with the secondary terminated in a load resistance R, as shown. This as a real transformer with a coupling coefficient k<1. Assuming AC excitation at a frequency @, derive 1₂ the frequency-dependent voltage transformation ratio V₂ (@)/(a) in terms of the turns ratio, coupling V coefficient, and mutual inductance L=k√ √LL₂ between the primary and secondary coils. Show that the imperfect coupling gives the circuit a low-pass characteristic with a time constant t = L₂(1-k²)/ R₂. Note the orientation of the windings in the figure, as well as the direction of current 72, which imply the following two-port network equations V₁ = jwL₂1₁-jwLm¹₂ V₂ = jwLm-jwL₂1₂ R₂

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Consider the transformer with the secondary terminated in a load resistance \( R_L \) as shown. This is a real transformer with a coupling coefficient \( k < 1 \). Assuming AC excitation at a frequency \( \omega \), derive the frequency-dependent voltage transformation ratio \( V_2(\omega)/V_1(\omega) \) in terms of the turns ratio, coupling coefficient, and mutual inductance \( L_m = k\sqrt{L_1L_2} \) between the primary and secondary coils. Show that the imperfect coupling gives the circuit a low-pass characteristic with a time constant \( \tau = L_2(1-k^2)/R_L \). Note the orientation of the windings in the figure, as well as the direction of current \( I_2 \), which imply the following two-port network equations:

\[ V_1 = j\omega L_1 I_1 - j\omega L_m I_2 \]

\[ V_2 = j\omega L_m I_1 - j\omega L_2 I_2 \]

**Diagram Explanation:**

- The diagram depicts a transformer with primary and secondary coils.
- The primary side has an input voltage \( V_1 \) and current \( I_1 \).
- The secondary side shows the output voltage \( V_2 \) and current \( I_2 \), connected to a load resistance \( R_L \).
- The coupling between the coils is less than perfect, represented by the coupling coefficient \( k \).
- Arrows indicate the direction of the currents \( I_1 \) and \( I_2 \) through the respective windings.
Transcribed Image Text:Consider the transformer with the secondary terminated in a load resistance \( R_L \) as shown. This is a real transformer with a coupling coefficient \( k < 1 \). Assuming AC excitation at a frequency \( \omega \), derive the frequency-dependent voltage transformation ratio \( V_2(\omega)/V_1(\omega) \) in terms of the turns ratio, coupling coefficient, and mutual inductance \( L_m = k\sqrt{L_1L_2} \) between the primary and secondary coils. Show that the imperfect coupling gives the circuit a low-pass characteristic with a time constant \( \tau = L_2(1-k^2)/R_L \). Note the orientation of the windings in the figure, as well as the direction of current \( I_2 \), which imply the following two-port network equations: \[ V_1 = j\omega L_1 I_1 - j\omega L_m I_2 \] \[ V_2 = j\omega L_m I_1 - j\omega L_2 I_2 \] **Diagram Explanation:** - The diagram depicts a transformer with primary and secondary coils. - The primary side has an input voltage \( V_1 \) and current \( I_1 \). - The secondary side shows the output voltage \( V_2 \) and current \( I_2 \), connected to a load resistance \( R_L \). - The coupling between the coils is less than perfect, represented by the coupling coefficient \( k \). - Arrows indicate the direction of the currents \( I_1 \) and \( I_2 \) through the respective windings.
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