Consider the titration of 50.0 ml of 1.00 M CHN by 0.500 M HC. For each volume of HCI added, decide which of the components is a major species after the HC has reacted completely. K for C₂H₂N- 1.7 x 10. 0.00ml HCI added no: H yes: H₂O no: CT yes: C₂H₂N Học CHINH HINT: Because no HCI has been added, this solution only contains a weak base and water. See text for discussion of weak base strong acid titrations. Previous Tries You are correct. Your receipt no. is 157-3511 30.00 ml HCI added Submit Answer no: H yes: H₂O Tries 0/45 yes: Cl yes: CN ð Calculate the pH at the equivalence point for this titration. yes: C₂H₂N HINT: Assume the added strong acid neutralizes (reacts completely with) the weak base present. You are correct. Your receipt no. is 157- 6783 Previous 100.00ml HCI added no: it yes: H₂0 yes: C no: C₂HN yes: CN HINT: Assume the added strong acid neutralizes (reacts completely with the weak base present. Determine the neutralization reaction then perform the stoichiometry calculation. See text for discussion of weak base-strong acid titrations. You are correct. Your receipt no is 157-1549 Submit Answer Tries 0/45 At what volume of HC added in this titration does the pH-5.237 Express your answer in ml and include the units in your answer. Previous Tries

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter14: Equilibria In Acid-base Solutions
Section: Chapter Questions
Problem 74QAP: Fifty cm3 of 1.000 M nitrous acid is titrated with 0.850 M NaOH. What is the pH of the solution (a)...
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Consider the major species present at the halfway point. From this, you should be able to deduce the order of the pH with onl
You are correct.
Previous Tries
Your receipt no. is 157-5402 2
2) Rank the following titrations in order of increasing pH at the equivalence point of the titration (1= lowest pH and 5 = hig
2 100.0 mL of 0.100 M HNO₂ (Ka = 4.0 x 104) by 0.100 M NaOH
3200.0 mL of 0.100 M (C₂Hs)2NH (Kb = 1.3 x 103) by 0.100 M HCI
4 100.0 mL of 0.100 M HC3H5O2 (Ka 1.3 x 105) by 0.100 M NaOH
100.0 mL of 0.100 M KOH by 0.100 M HCI
100.0 mL of 0.100 M NH3 (Kb = 1.8 x1 05) by 0.100 M HCI
Consider the major species present at the equivalence point. From this, you should be able to deduce the order of the pH with
Consider the titration of 50.0 mL of 1.00 M CH₂N by 0.500 M HC.
For each volume of HCI added, decide which of the components is a major species after the HCI has reacted completely.
K for CHN 1.7 x 10.
0.00 ml HCT added
no: H
yes: H₂O
по: ст
yes: C₂H₂N
HỌC CHINH
HINT: Because no HCI has been added, this solution
only contains a weak base and water. See text for
discussion of weak base-strong acid titrations.
Previous Tries
You are correct.
Your receipt no. is 157-3511
30.00 mL HCI added
no: H
yes: H₂O
yes: C
yes: CH₂N
yes: CH NH
HINT: Assume the added strong acid
neutralizes (reacts completely with) the
weak base present.
You are correct.
Your receipt no. is 157-
6783
Previous
Tries
100.00 ml.HCI added
no: H
yes: H₂0
yes: C
no: CHN
yes: CH NH
HINT: Assume the added strong acid neutralizes (reacts completely with)
the weak base present. Determine the neutralization reaction then perform
the stoichiometry calculation. See text for discussion of weak base-strong
acid titrations,
You are correct.
Your receipt no, is 157-1549
Previous Tries
Calculate the pH at the equivalence point for this titration.
Submit Answer Tries 0/45
At what volume of HCI added in this titration does the pH 5,237 Express your answer in ml, and include the units in your answer.
Submit Answer Tries 0/45
Transcribed Image Text:Consider the major species present at the halfway point. From this, you should be able to deduce the order of the pH with onl You are correct. Previous Tries Your receipt no. is 157-5402 2 2) Rank the following titrations in order of increasing pH at the equivalence point of the titration (1= lowest pH and 5 = hig 2 100.0 mL of 0.100 M HNO₂ (Ka = 4.0 x 104) by 0.100 M NaOH 3200.0 mL of 0.100 M (C₂Hs)2NH (Kb = 1.3 x 103) by 0.100 M HCI 4 100.0 mL of 0.100 M HC3H5O2 (Ka 1.3 x 105) by 0.100 M NaOH 100.0 mL of 0.100 M KOH by 0.100 M HCI 100.0 mL of 0.100 M NH3 (Kb = 1.8 x1 05) by 0.100 M HCI Consider the major species present at the equivalence point. From this, you should be able to deduce the order of the pH with Consider the titration of 50.0 mL of 1.00 M CH₂N by 0.500 M HC. For each volume of HCI added, decide which of the components is a major species after the HCI has reacted completely. K for CHN 1.7 x 10. 0.00 ml HCT added no: H yes: H₂O по: ст yes: C₂H₂N HỌC CHINH HINT: Because no HCI has been added, this solution only contains a weak base and water. See text for discussion of weak base-strong acid titrations. Previous Tries You are correct. Your receipt no. is 157-3511 30.00 mL HCI added no: H yes: H₂O yes: C yes: CH₂N yes: CH NH HINT: Assume the added strong acid neutralizes (reacts completely with) the weak base present. You are correct. Your receipt no. is 157- 6783 Previous Tries 100.00 ml.HCI added no: H yes: H₂0 yes: C no: CHN yes: CH NH HINT: Assume the added strong acid neutralizes (reacts completely with) the weak base present. Determine the neutralization reaction then perform the stoichiometry calculation. See text for discussion of weak base-strong acid titrations, You are correct. Your receipt no, is 157-1549 Previous Tries Calculate the pH at the equivalence point for this titration. Submit Answer Tries 0/45 At what volume of HCI added in this titration does the pH 5,237 Express your answer in ml, and include the units in your answer. Submit Answer Tries 0/45
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