Consider the titration of 100.0 mL of 0.250 M aniline ( Kh= 3.8 x 1010 with 0.500M HC1. For calculating the volume of HCl required to reach a pH of 8.0, which of the following expressions is correct? (X = volume in mL ofHCl required to reach a pH of 8.0) O a. 0.5x (100) (0.25) = [aniline] 100+ x O b H]= x O c. 05x -= [aniline] 100+x O d. 25-0.5x - 10 = [aniline] 100 +x e. none of these
Consider the titration of 100.0 mL of 0.250 M aniline ( Kh= 3.8 x 1010 with 0.500M HC1. For calculating the volume of HCl required to reach a pH of 8.0, which of the following expressions is correct? (X = volume in mL ofHCl required to reach a pH of 8.0) O a. 0.5x (100) (0.25) = [aniline] 100+ x O b H]= x O c. 05x -= [aniline] 100+x O d. 25-0.5x - 10 = [aniline] 100 +x e. none of these
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![QUESTION 14
Consider the titration of 100.0 mL of 0.250 M aniline ( Kh= 3.8 × 1010) with 0.500 M HC1 For calculating the volume of HCl required to
%3D
reach a pH of 8.0, which of the following expressions is corect? ( X = volume in mL of HCl required to reach a pH of 8.0)
O a. 0.5x (100)(0. 25) - Janiline]
|3|
100+x
Ob:H] =x
O C. 05x
= [aniline]
100+x
O d. 25-0.5x
10 = [aniline]
|
100+x
e. none of these](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F98b8792e-a762-4603-ab47-5c8bbf0c3635%2F5dad2dc7-a805-4fb4-9b5e-1e3b55eb0154%2Fnzi4bej_processed.jpeg&w=3840&q=75)
Transcribed Image Text:QUESTION 14
Consider the titration of 100.0 mL of 0.250 M aniline ( Kh= 3.8 × 1010) with 0.500 M HC1 For calculating the volume of HCl required to
%3D
reach a pH of 8.0, which of the following expressions is corect? ( X = volume in mL of HCl required to reach a pH of 8.0)
O a. 0.5x (100)(0. 25) - Janiline]
|3|
100+x
Ob:H] =x
O C. 05x
= [aniline]
100+x
O d. 25-0.5x
10 = [aniline]
|
100+x
e. none of these
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