Consider the table below gives the probabilities of the distribution of random variable X.Value of X P(X=x)(denoted by x) f(x)01234567 0080.14bC0.100.130.13d0.020.01In reference to the table, suppose that b = f(1) =0.2 and c = f(2)= 0.06. What is the probability P(X ≥ 4) equal to?

Given: b = f(1) = 0.2 c = f(2) = 0.06

Answered: Consider the table below gives the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The probabilities of all the values of a random variableX must: OA. average to a small and negative number. OB. add up to 1. OC. average to 0. D. none of the above,
В2. (a) Given the probability Venn diagram below for the two Events A and B find the probabilities: 0.6 0.5 A 0.2 (i) (ii) (iii) Pr( A 'OR' B) Pr( Not-A 'AND' Not-B) Pr( Not-A "OR' Not-B) (b) A random sample from a population of X with unknown mean but a known variance, o = 400, gives the following data: sample size, n= 125, Ex= 1750. (i) Give a point estimate of the population mean, u. (ii) Is this estimate biased or not. Give a reason. (ii) Derive a 95% confidence interval for the population mean, µ.
МАТH1208 QUESTION 2 А. The table below shows the probability distribution of the likelihood of the number of SUVS in a household in Forest Hill, St Andrew. Number of 2 3 SUVS (x) P(X = x) 0.05 0.12 0.60 0.20 Find: i. The value of 'c' ( the probability of 4 SUVS in a household) ii. The expected value [E(X) ], the mean value of SUVS in a household iii. The variance iv. standard deviation of SUVS in a household
For families with 5 children, let XX be the number of children with Genetic Condition B. Can the following table be a probability distribution for the random variable XX? xx P(x)P(x) 1 0.2077 2 0.0943 3 0.3281 4 0.1105 5 0.3232 A. yes B. noIs it correct answer B?
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Q P.6: On its way, a car meets 4 traffic lights, and the probability that each of them will be red is 0.5. Let X be a discrete random variable equal to the number of traffic lights that were green when the car arrived. X may take the values of 0, 1, 2, 3, 4. (Assume traffic lights are independent.) What is the probability distribution of X? The probability distribution of X is 3 4 p(x) 0.5 0.25 0.125 0.0625 0.0625 The probability of distribution of X is 3 p(x) 0.5 0.5 0.25 0.125 The probability of distribution of X is 3 4 p(x) 0.5 0.25 0.5 0.25 0.125 The probability distribution of X is 1 3 4 p(x) | 0.5 || 0.5 || 0.5 | 0.5 || 0.5 The probability of distribution of X is 3 4 p(x) || 0.0625 0.0625 0.125 0.25 0.5
For families with 5 children, let XX be the number of children with Genetic Condition B. Can the following table be a probability distribution for the random variable XX? xx P(x)P(x) 1 0.2486 2 0.347 3 0.182 4 0.0226 5 0.3492 yes no
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0.10.20.40.5
2. A random variable|x has the following probability distribution. Find the value of p and then evaluate the following probabilities: P(X 5) and P(0 < X < 6). Find the mean of the probability distribution. 1 3 4 6 17 P(X) 2p 2p 3p p2 2p2 7p? + p Value of p = P(X < 5) =. P(X 2 5) = P(0 < X < 5) = Mean (u) =

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