Consider the system x-2y3z = 1 2x + ky+6= = 6 -x + 3y + (k-3)==0 a. Find all values of k for which the system has no solutions. b. Find all values of k for which the system has a unique solution. c. Find all values of k for which the system has infinitely many solutions and write the general solution in this situation.
Consider the system x-2y3z = 1 2x + ky+6= = 6 -x + 3y + (k-3)==0 a. Find all values of k for which the system has no solutions. b. Find all values of k for which the system has a unique solution. c. Find all values of k for which the system has infinitely many solutions and write the general solution in this situation.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Consider the system
\[ \begin{cases}
x - 2y - 3z = 1 \\
2x + ky + 6z = 6 \\
-x + 3y + (k - 3)z = 0
\end{cases} \]
**Tasks:**
a. Find all values of \(k\) for which the system has no solutions.
b. Find all values of \(k\) for which the system has a unique solution.
c. Find all values of \(k\) for which the system has infinitely many solutions and write the general solution in this situation.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe6e77107-ef1d-4e39-badf-4decafa47f1b%2Fd6a963a6-0bc9-4954-996d-857e3545a33a%2F5fmcb7e_processed.png&w=3840&q=75)
Transcribed Image Text:Consider the system
\[ \begin{cases}
x - 2y - 3z = 1 \\
2x + ky + 6z = 6 \\
-x + 3y + (k - 3)z = 0
\end{cases} \]
**Tasks:**
a. Find all values of \(k\) for which the system has no solutions.
b. Find all values of \(k\) for which the system has a unique solution.
c. Find all values of \(k\) for which the system has infinitely many solutions and write the general solution in this situation.
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