Consider the systemshown in Fig. P6.86. The ropeand pulley have negligible mass,and the pulley is frictionless. The coefficient of kinetic fric-tion between the 8.00-kg block and the tabletop isThe blocks are released from rest. Use energy methods to cal-culate the speed of the 6.00-kg block after it has descended

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A: Recall KE=1/2mv^2 m=1800kg v=40km/hr=11.11m/s

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A: As per guidelines i have solved the first question.

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A: m=80 kgvi=1 m/svf=3.5 m/st=1.5 s

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Q: Vo Yma

A: The solution can be given as follows :-

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