Consider the system of masses at left. (2) Two masses are connected by a light string and hung over a light, frictionless pulley (meaning we can neglect the masses of the string and pulley, and any friction forces in the equations). We will specify that the positive x-direction is to the left over the pulley as shown. direction means that m, drops while m2 rises. (Now consider the opposite - what motion in the negative direction would mean.) +x Thus motion in the positive W, m Free body diagrams are also shown for both hanging masses. Using separate instances of Newton's 2nd Law for these two masses, derive a single theoretical equation that solves for the acceleration of the system in terms of the unknowns and g. Hint: the tension should not be one of these unknowns. m. W, (3) (2). Assuming we take several trials where the total mass m, +m2 is Consider the setup and the equation you derived in Problem istribute the masses between m, and m,. The equation you derived ---- ----►
Consider the system of masses at left. (2) Two masses are connected by a light string and hung over a light, frictionless pulley (meaning we can neglect the masses of the string and pulley, and any friction forces in the equations). We will specify that the positive x-direction is to the left over the pulley as shown. direction means that m, drops while m2 rises. (Now consider the opposite - what motion in the negative direction would mean.) +x Thus motion in the positive W, m Free body diagrams are also shown for both hanging masses. Using separate instances of Newton's 2nd Law for these two masses, derive a single theoretical equation that solves for the acceleration of the system in terms of the unknowns and g. Hint: the tension should not be one of these unknowns. m. W, (3) (2). Assuming we take several trials where the total mass m, +m2 is Consider the setup and the equation you derived in Problem istribute the masses between m, and m,. The equation you derived ---- ----►
Related questions
Question
consider the setup from Problem(2). Assume ?1 =4.00kg. ?2 =10.00kg, and no friction.
(a)What is the magnitude of the acceleration of the system?
(b)Specify in what directionthe systemisaccelerating.
(c)What is the tension in the string?
![Consider the system of masses at left.
(2)
Two masses are connected by a light string and
hung over a light, frictionless pulley (meaning we
++
can neglect the masses of the string and pulley, and
any friction forces in the equations). We will specify
that the positive x-direction is to the left over the
pulley as shown. Thus motion in the positive
direction means that m, drops while m2 rises. (Now
consider the opposite - what motion in the negative
direction would mean.)
m,
W,
afar
%3D
T
om.j
Free body diagrams are also shown for both hanging masses. Using
separate instances of Newton's 2nd Law for these two masses, derive
a single theoretical equation that solves for the acceleration of the
system in terms of the unknowns and g. Hint: the tension should not
be one of these unknowns.
+x:
m,
W,
Consider the setup and the equation you derived in Problem
(3)
(2). Assuming we take several trials where the total mass m, + m, is
constant, but we redistribute the masses between m, and m,. The equation you derived
as your answer to the Problem (2) would apply.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd6d74955-2c6e-4482-bafd-6df7ec074c1a%2F499b586a-e163-40ce-9b41-e171ef6e965a%2F7a7vp4q_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Consider the system of masses at left.
(2)
Two masses are connected by a light string and
hung over a light, frictionless pulley (meaning we
++
can neglect the masses of the string and pulley, and
any friction forces in the equations). We will specify
that the positive x-direction is to the left over the
pulley as shown. Thus motion in the positive
direction means that m, drops while m2 rises. (Now
consider the opposite - what motion in the negative
direction would mean.)
m,
W,
afar
%3D
T
om.j
Free body diagrams are also shown for both hanging masses. Using
separate instances of Newton's 2nd Law for these two masses, derive
a single theoretical equation that solves for the acceleration of the
system in terms of the unknowns and g. Hint: the tension should not
be one of these unknowns.
+x:
m,
W,
Consider the setup and the equation you derived in Problem
(3)
(2). Assuming we take several trials where the total mass m, + m, is
constant, but we redistribute the masses between m, and m,. The equation you derived
as your answer to the Problem (2) would apply.
Expert Solution
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Step 1
Given:
The mass of the block is 4 kg.
The mass of the block is 10 kg.
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