Consider the system of differential equations For this system, the smaller eigenvalue is (-39/10) [Note-- you may want to view a phase plane plot (right click to open in a new window).] If y' = Ay is a differential equation, how would the solution curves behave? • All of the solutions curves would converge towards 0. (Stable node) All of the solution curves would run away from 0. (Unstable node) The solution curves would race towards zero and then veer away towards infinity. (Saddle) The solution curves converge to different points. dx dt dy dt = -1.4x +0.75y, = 1.66667-3.4y. and the larger eigenvalue is (-9/10)

Advanced Engineering Mathematics
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Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Consider the system of differential equations
For this system, the smaller eigenvalue is (-39/10)
[Note-- you may want to view a phase plane plot (right click to open in a new window).]
If y'= Ay is a differential equation, how would the solution curves behave?
• All of the solutions curves would converge towards 0. (Stable node)
All of the solution curves would run away from 0. (Unstable node)
and the larger eigenvalue is
The solution curves would race towards zero and then veer away towards infinity. (Saddle)
The solution curves converge to different points.
The solution to the above differential equation with initial values (0) = 4, y(0) = 3 is
(t)=
(49/12)*e^((-9/10)*t)-(1/12)*e^((-19/10)*t)
y(t) = (49/12)*e^((-9/10)*t)+(5/12)*e^((-19/10)*t)
da
dt
dy
dt
= -1.4x +0.75y,
= 1.66667 3.4y.
(-9/10)
Transcribed Image Text:Consider the system of differential equations For this system, the smaller eigenvalue is (-39/10) [Note-- you may want to view a phase plane plot (right click to open in a new window).] If y'= Ay is a differential equation, how would the solution curves behave? • All of the solutions curves would converge towards 0. (Stable node) All of the solution curves would run away from 0. (Unstable node) and the larger eigenvalue is The solution curves would race towards zero and then veer away towards infinity. (Saddle) The solution curves converge to different points. The solution to the above differential equation with initial values (0) = 4, y(0) = 3 is (t)= (49/12)*e^((-9/10)*t)-(1/12)*e^((-19/10)*t) y(t) = (49/12)*e^((-9/10)*t)+(5/12)*e^((-19/10)*t) da dt dy dt = -1.4x +0.75y, = 1.66667 3.4y. (-9/10)
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