Consider the system of components connected as in the accompanying picture. Components 1 and 2 are connected in parallel, so that subsystem works if and only if either 1 or 2 works; since 3 and 4 are connected in series, that subsystem works if and only if both 3 and 4 work. If components work independently of one another and P(component i works) = 0.82 for  i = 1, 2  and = 0.69 for  i = 3, 4,  calculate P(system works). (Round your answer to four decimal places.)

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Consider the system of components connected as in the accompanying picture. Components 1 and 2 are connected in parallel, so that subsystem works if and only if either 1 or 2 works; since 3 and 4 are connected in series, that subsystem works if and only if both 3 and 4 work. If components work independently of one another and P(component i works) = 0.82 for 

i = 1, 2

 and = 0.69 for 

i = 3, 4,

 calculate P(system works). (Round your answer to four decimal places.)

 
Expert Solution
Step 1

The probability of working parallel components is the probability of the union of components.

The probability of the union of events M and N is as follows.

P(MN)=P(M)+P(N)-P(MN)

And the probability of working of a series of components is the probability of the intersection of components.

If the events are independent then their probability of intersection is as follows.

P(MN)=P(M)P(N)

Given that,

Two components are C1  and C2 in parallel.  It is subsystem A

Two components are C3 and C4 in series. It is subsystem B

The components are workers independently.

The probability of components works is given below.

P(C1)=0.82P(C2)=0.82P(C3)=0.69P(C4)=0.69

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