Consider the surface, S. given by the portion of the parabaloid z = 5-3²-8y² above the xy-plane (where > 0). A flow field is given by F = <4y, 6x, 5xy>. Which of the following integrals gives the flux across the surface S? [[ (4y+6x)√1 +2³²+3² d$ (C) _{[ƒ*√/1+16r² + 363+² dS _^) √√(5-37²-8y²³)√ D) ff√1+36x² + 256y²dS (E) G) √ √1 +92 +64y+dS dS (H) [J*60√1+36x² +256y² dS ²−8y²)√1 +9x² +64y² dS (B) ff(4y+6x)√1+x² + y² d$ (C) 125xy V1+36x²+256y dS (F) 4y +6x + 5xy √1+6² +16y² dS
Consider the surface, S. given by the portion of the parabaloid z = 5-3²-8y² above the xy-plane (where > 0). A flow field is given by F = <4y, 6x, 5xy>. Which of the following integrals gives the flux across the surface S? [[ (4y+6x)√1 +2³²+3² d$ (C) _{[ƒ*√/1+16r² + 363+² dS _^) √√(5-37²-8y²³)√ D) ff√1+36x² + 256y²dS (E) G) √ √1 +92 +64y+dS dS (H) [J*60√1+36x² +256y² dS ²−8y²)√1 +9x² +64y² dS (B) ff(4y+6x)√1+x² + y² d$ (C) 125xy V1+36x²+256y dS (F) 4y +6x + 5xy √1+6² +16y² dS
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Problem #9: Consider the surface, S, given by the portion of the parabaloid z = 5-3x²-8y² above the xy-plane (where : >
0). A flow field is given by F=<4y, 6x, 5xy>. Which of the following integrals gives the flux across the surface
S?
(A) S (5-34²-8y²)√/1 + 9x² +64y² d5 (B) ff (4y + 6x)√]
(D) √1+36x² + 256y² dS (E)
) ਨੂੰ 64,78
√1+9x² + 64y
(G)
dS (H)
125xy
V1 + 36x² + 256y²
zdS (F) ff
√560 √/1 + 36x²
-11
2+ y² dS (C) f√1+
√1+ 16x²+36y2 S
+36x² +256y²dS
4y +6x + 5xy
√1+ 6x² + 16y² S](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4ad229d2-94c2-4360-b0ca-273c76ee826c%2F475df640-9415-4fae-948d-74a95d7ec49b%2Frmbgmwx_processed.png&w=3840&q=75)
Transcribed Image Text:Problem #9: Consider the surface, S, given by the portion of the parabaloid z = 5-3x²-8y² above the xy-plane (where : >
0). A flow field is given by F=<4y, 6x, 5xy>. Which of the following integrals gives the flux across the surface
S?
(A) S (5-34²-8y²)√/1 + 9x² +64y² d5 (B) ff (4y + 6x)√]
(D) √1+36x² + 256y² dS (E)
) ਨੂੰ 64,78
√1+9x² + 64y
(G)
dS (H)
125xy
V1 + 36x² + 256y²
zdS (F) ff
√560 √/1 + 36x²
-11
2+ y² dS (C) f√1+
√1+ 16x²+36y2 S
+36x² +256y²dS
4y +6x + 5xy
√1+ 6x² + 16y² S
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