Consider the surface integral J. F· dS, S where F(x, y, z) = (xye², xy', -ye²) and S is the surface of the box bounded by the coordinate planes and the planes x = : 1, y = 2 and z = 3. (a) The divergence theorem allows us to express the surface integral as a triple iterated integral of the form a g(х, у, z) dx dy dz, where a is the constant b is the constant c is the constant g(x, y, z) is a function that satisfies g(2, 3, 4) = (b) The value of the surface integral is

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Consider the surface integral
F. dS,
where F(x, y, z) = (xye², xy', – ye²) and S is the surface of the box bounded by the coordinate planes
and the planes x =
1, у
2 and z =
3.
(a) The divergence theorem allows us to express the surface integral as a triple iterated integral of the form
a
b
g(x, y, z) dx dy dz,
where a is the constant
b is the constant
c is the constant
g(x, y, z) is a function that satisfies g(2, 3, 4) =
(b) The value of the surface integral is
Transcribed Image Text:Consider the surface integral F. dS, where F(x, y, z) = (xye², xy', – ye²) and S is the surface of the box bounded by the coordinate planes and the planes x = 1, у 2 and z = 3. (a) The divergence theorem allows us to express the surface integral as a triple iterated integral of the form a b g(x, y, z) dx dy dz, where a is the constant b is the constant c is the constant g(x, y, z) is a function that satisfies g(2, 3, 4) = (b) The value of the surface integral is
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