Consider the subspace spanned by B = {cos(x), sin(x), x cos(x), x sin(x)} inside the space of continuous functions. B is in fact a basis for its span. The derivative is a linear transformation on this span, and it acts as follows: D(cos(x)) = – sin(x) D(sin(x)) = cos(x) D(x cos(x)) = cos(x) – x sin(x) D(r sin(x)) = sin(x) + x cos(x) Find the matrix representing D in this basis. Use this to compute D(3 cos(x) – 2 sin(x) + x cos(x) – 2x sin(x)) without computing any derivatives. (show the matrix and column vector you use to do this, and the resulting column vector before converting back to functions)

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### Linear Algebra Basis and Derivative Transformation

#### Problem Statement
Consider the subspace spanned by \( B = \{\cos(x), \sin(x), x \cos(x), x \sin(x)\} \) inside the space of continuous functions. \( B \) is in fact a basis for its span. The derivative is a linear transformation on this span, and it acts as follows:

\[
D(\cos(x)) = -\sin(x)
\]

\[
D(\sin(x)) = \cos(x)
\]

\[
D(x \cos(x)) = \cos(x) - x \sin(x)
\]

\[
D(x \sin(x)) = \sin(x) + x \cos(x)
\]

#### Task:

Find the matrix representing \( D \) in this basis. Use this to compute:

\[
D(3 \cos(x) - 2 \sin(x) + x \cos(x) - 2x \sin(x))
\]

without computing any derivatives. Show the matrix and column vector you use to do this, and the resulting column vector before converting back to functions.

#### Solution:

1. **Derivatives in Terms of Basis:**

- \( D(\cos(x)) = -\sin(x) \rightarrow -\sin(x) \)
- \( D(\sin(x)) = \cos(x) \rightarrow \cos(x) \)
- \( D(x \cos(x)) = \cos(x) - x \sin(x) \rightarrow \cos(x) - x \sin(x) \)
- \( D(x \sin(x)) = \sin(x) + x \cos(x) \rightarrow \sin(x) + x \cos(x) \)

2. **Express Derivatives as Linear Combinations of the Basis:**

- \( D(\cos(x)) = -\sin(x) \rightarrow [0,-1,0,0] \)
- \( D(\sin(x)) = \cos(x) \rightarrow [1,0,0,0] \)
- \( D(x \cos(x)) = \cos(x) - x \sin(x) \rightarrow [1,0,0,-1] \)
- \( D(x \sin(x)) = \sin(x) + x \cos(x) \rightarrow [0,1,1,0] \)

3. **Matrix Representation:**

The matrix \( [D] \) that
Transcribed Image Text:### Linear Algebra Basis and Derivative Transformation #### Problem Statement Consider the subspace spanned by \( B = \{\cos(x), \sin(x), x \cos(x), x \sin(x)\} \) inside the space of continuous functions. \( B \) is in fact a basis for its span. The derivative is a linear transformation on this span, and it acts as follows: \[ D(\cos(x)) = -\sin(x) \] \[ D(\sin(x)) = \cos(x) \] \[ D(x \cos(x)) = \cos(x) - x \sin(x) \] \[ D(x \sin(x)) = \sin(x) + x \cos(x) \] #### Task: Find the matrix representing \( D \) in this basis. Use this to compute: \[ D(3 \cos(x) - 2 \sin(x) + x \cos(x) - 2x \sin(x)) \] without computing any derivatives. Show the matrix and column vector you use to do this, and the resulting column vector before converting back to functions. #### Solution: 1. **Derivatives in Terms of Basis:** - \( D(\cos(x)) = -\sin(x) \rightarrow -\sin(x) \) - \( D(\sin(x)) = \cos(x) \rightarrow \cos(x) \) - \( D(x \cos(x)) = \cos(x) - x \sin(x) \rightarrow \cos(x) - x \sin(x) \) - \( D(x \sin(x)) = \sin(x) + x \cos(x) \rightarrow \sin(x) + x \cos(x) \) 2. **Express Derivatives as Linear Combinations of the Basis:** - \( D(\cos(x)) = -\sin(x) \rightarrow [0,-1,0,0] \) - \( D(\sin(x)) = \cos(x) \rightarrow [1,0,0,0] \) - \( D(x \cos(x)) = \cos(x) - x \sin(x) \rightarrow [1,0,0,-1] \) - \( D(x \sin(x)) = \sin(x) + x \cos(x) \rightarrow [0,1,1,0] \) 3. **Matrix Representation:** The matrix \( [D] \) that
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