Consider the solution below to this: “Prove that if A is a set then so is {A} but do NOT use an argument that involves stages explicitly”. “Proof.” We know (NOTEs!) that, for any sets A and B, {A,B} is a set. But {A} ⊆ {A, B}, so {A} is a set by the subclass theorem. What EXACTLY is wrong with the proof above?

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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  1. Consider the solution below to this:

    “Prove that if A is a set then so is {A} but do NOT use an argument that involves stages explicitly”.

    “Proof.” We know (NOTEs!) that, for any sets A and B, {A,B} is a set. But {A} ⊆ {A, B}, so {A} is a set by the subclass theorem.

    What EXACTLY is wrong with the proof above?

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