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Consider the solid Q bounded by the surfaces: S1 : y = 4 – x², S2: z = 4 – r, S3 : S4 : y = 0 %3D whose graphical representation is: Let S be the boundary of the solid Q (i.e., S= S1 u S2 U S3 U 4). An integral that allows to determine the value of F.n dS where n is the unit normal vector exterior to S and F(x, y, z) = (83, v, 2), is:

Consider the solid Q bounded by the surfaces: S1 : y = 4 – x², S2: z = 4 – r, S3 : S4 : y = 0 %3D whose graphical representation is: Let S be the boundary of the solid Q (i.e., S= S1 u S2 U S3 U 4). An integral that allows to determine the value of F.n dS where n is the unit normal vector exterior to S and F(x, y, z) = (83, v, 2), is:

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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6) Answer the question shown in the images 

A) -2 Jo 4-z A) dz dy dr -2 B) (z +2) dz dy dx -2 Jo 2 C) dz dy dx -4-x D) (z + 2) dz dy dr
Transcribed Image Text:A) -2 Jo 4-z A) dz dy dr -2 B) (z +2) dz dy dx -2 Jo 2 C) dz dy dx -4-x D) (z + 2) dz dy dr
Consider the solid Q bounded by the surfaces: S1 : y = 4 – x², S2: z = 4 – r, S3 : S4 : y = 0 %3D whose graphical representation is: Let S be the boundary of the solid Q (i.e., S= S1 u S2 U S3 U 4). An integral that allows to determine the value of F.n dS where n is the unit normal vector exterior to S and F(x, y, z) = (83, v, 2), is:
Transcribed Image Text:Consider the solid Q bounded by the surfaces: S1 : y = 4 – x², S2: z = 4 – r, S3 : S4 : y = 0 %3D whose graphical representation is: Let S be the boundary of the solid Q (i.e., S= S1 u S2 U S3 U 4). An integral that allows to determine the value of F.n dS where n is the unit normal vector exterior to S and F(x, y, z) = (83, v, 2), is:
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