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Consider the situation in the figure - a student diver in a pool and an instructor on the edge, outside the water. Since the indices of refraction of air and water are different, the light rays coming from the diver and the instructor are refracted at the surface, changing their apparent position with respect to each other. The diver sees the instructor at an apparent angle of 0₂ = 35°, measured from the normal to the interface.

Consider the situation in the figure - a student diver in a pool and an instructor on the edge, outside the water. Since the indices of refraction of air and water are different, the light rays coming from the diver and the instructor are refracted at the surface, changing their apparent position with respect to each other. The diver sees the instructor at an apparent angle of 0₂ = 35°, measured from the normal to the interface.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Consider the situation in the figure - a student diver in a pool and an instructor on the edge, outside the water. Since the indices of refraction of air and water are different, the light rays coming from the diver and the instructor are refracted at the surface, changing their apparent position with respect to each other. The diver sees the instructor at an apparent angle of 0 = 35°, measured from the normal to the interface. Known Variables 0₂=35° 945 Find the height of the instructor's head above the water in meters, noting that you will first have to = 1.33 calculate the angle of incidence (you can take the indices of refraction to be n = 1 for air and n for water). h = Find the apparent depth of the diver's head below water as seen by the instructor in meters, assuming the diver and his image both have the same horizontal distance along the surface of the water. x=
Transcribed Image Text:Consider the situation in the figure - a student diver in a pool and an instructor on the edge, outside the water. Since the indices of refraction of air and water are different, the light rays coming from the diver and the instructor are refracted at the surface, changing their apparent position with respect to each other. The diver sees the instructor at an apparent angle of 0 = 35°, measured from the normal to the interface. Known Variables 0₂=35° 945 Find the height of the instructor's head above the water in meters, noting that you will first have to = 1.33 calculate the angle of incidence (you can take the indices of refraction to be n = 1 for air and n for water). h = Find the apparent depth of the diver's head below water as seen by the instructor in meters, assuming the diver and his image both have the same horizontal distance along the surface of the water. x=
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